如何将数据结构转换为另一种树结构 来自 API 的 JSON输出如下结构

如何解决如何将数据结构转换为另一种树结构 来自 API 的 JSON输出如下结构

我需要您的帮助来使用给定的 JSON 创建一个树状数据结构，如下所示，所需的输出结构已经在下面给出。我是编程初学者，我对数据结构只有一点点了解

来自 API 的 JSON

   [
    "",[
        "Test",[
            "Test/sample",[
                "Test/sample/sample1"
            ]
        ],[
            "Test/test3"
        ]
    ],[
        "Test1",[
            "Test1/test2"
        ]
    ],[
        "cat"
    ]
]

输出如下结构

 {
        "key": "Image","label": "Image","icon": 'pi pi-folder',"children": []
    },{
        "key": "Test","label": "Test","icon": "pi pi-folder","children": [
            {
                "key": "Test/sample","label": "Sample","children": [{
                    "key": "Test/sample/sample1","label": "Sample1","children": []
                }]
            },{
                "key": "Test/test3","label": "test3","children": []
            },]
    },{
        "key": "Test1","label": "Test1","children": [{
            "key": "Test1/test2","label": "test2","children": []
        }]
    },{
        "key": "cat","label": "cat",]

以上结构为图片文件目录，目录名用标签表示，图标表示目录，子目录表示子目录

Console value of API

解决方法

它可以通过递归函数轻松归档

const icon = "pi pi-folder";
var a = [
    "",[
        "Test",[
            "Test/sample",[
                "Test/sample/sample1"
            ]
        ],[
            "Test/test3"
        ]
    ],[
        "Test1",[
            "Test1/test2"
        ]
    ],[
        "cat"
    ]
]

/**
 * @param {Array} arr The child array
 */
function createChildNode(arr) {
    let key = "Image";
    let label = "Image";
    let children = [];
    if (arr.length >= 1) {
        key = arr[0];
        label = key.includes("/") ? key.split("/").pop() : key;
        label = label.charAt(0).toUpperCase() + label.slice(1);
        for (let index = 1; index < arr.length; index++) {
            const element = arr[index];
            children.push(createChildNode(element));
        }
    }
    return {key: key,label: label,icon: icon,children: children};
}

var b = []
for (let index = 0; index < a.length; index++) {
    const element = a[index];
    b.push(createChildNode(element));
}
console.log(b);