Python：TypeError：'float'对象不可迭代

如何解决Python：TypeError：'float'对象不可迭代

在遍历元组列表时，我尝试使用为任何两行访问的值在 python 中进行计算，但我收到如下类型错误。有谁知道如何解决这个问题？谢谢！

代码如下：

for ws1 in ccy_results:
            for ws2 in ccy_results:
                variance = ws1.WS * ws2.WS
                K += variance

错误信息：

    K += variance
TypeError: 'float' object is not iterable

ccy_results 的摘录如下所示：

[ws(Qualifier='AUD',Curve='Libor3m',Tenor='1m',WS=214000000.0),ws(Qualifier='AUD',Tenor='2y',WS=-106000000.0),Tenor='6m',WS=213000000.0),ws(Qualifier='CHF',Curve='Libor6m',Tenor='15y',WS=-200000000.0),Tenor='20y',WS=540000000.0),Tenor='30y',WS=756000000.0)]

我尝试通过使用以下代码打印 ws1.WS 来进行检查，但是 ccy_results 中的所有 WS 都出现了。我想这就是原因。我该如何解决这个问题？

for ws1 in ccy_results:
            for ws2 in ccy_results:
                print(ws1.WS)

---

import collections
ws = collections.namedtuple('ws',('Qualifier','Curve','Tenor','WS'))
ccy_results = [ws(Qualifier='AUD',WS=756000000.0)]
K = []
for ws1 in ccy_results:
    for ws2 in ccy_results:
        variance = ws1.WS * ws2.WS
        K += variance

解决方法

列表的增广赋值操作 awk ' ##Starting awk program from here. FNR==NR{ ##Checking condition which will be TRUE when Input_file is being read first time. arr[$NF]++ ##Creating arr with index of last field and increasing it 1 each time it comes with same one. next ##next will skip all further statements from here. } arr[$NF]==1{ ##Checking condition if any value(last field) occurs only 1 time in whole Input_file then do following. print > ("unique.txt") ##Printing current line to unique.txt output file. next ##next will skip all further statements from here. } arr[$NF]>1{ ##Checking condition if last field comes more than 1 then do following. outFile=$NF".txt" ##Creating outFile variable with last field .txt to it. print >> (outFile) ##Printing current line to output file here. close(outFile) ##Closing output file in backend to avoid "too many opened files" error. } ' Input_file Input_file ##Mentioning Input_file(s) here. 等价于 +=，它的参数（表达式的左侧）期望一个可迭代对象.

改变

list.extend

到

K += variance

---

来自Mutable Sequence Types

操作	结果
s.extend(t) 或 s += t	用 t 的内容扩展 s（大部分与 s[len(s):len(s)] = t 相同）