如何解决在break语句后将变量传递给迭代变量
如何让迭代变量i在跳出循环后取变量lc的值？谢谢你。代码如下：
a = [155,157,83,121,112,137,129,159]
b = [145,148,66,117,101,131,107,153]
i = 0
high = a[0]
while i < len(a):
if a[i] > high:
high = a[i]
for j in range(i,len(a)):
if a[j] > high:
lv = min(b[i:j])
lc = b.index(lv,i,j)
dd = (lv/high-1)*100
print(high,lv,dd)
high = a[lc]
break
i += 1
解决方法
您的代码：
a = [155,157,83,121,112,137,129,159]
b = [145,148,66,117,101,131,107,153]
i = 0
high = a[0]
while i < len(a):
print(i,end=',')
if a[i] > high:
high = a[i]
for j in range(i,len(a)):
if a[j] > high:
lv = min(b[i:j])
lc = b.index(lv,i,j)
dd = (lv/high-1)*100
# print(high,lv,dd)
high = a[lc]
break
i += 1
输出：
0,1,2,3,4,5,6,7,你是这个意思吗？
i = 0
high = a[0]
while i < len(a):
print(i,')
flag_add = False
if a[i] > high:
high = a[i]
for j in range(i,dd)
high = a[lc]
flag_add = True
break
i = lc if flag_add else i
i += 1
输出：
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