在 Spring WebService 中设置 wsa:To:

如何解决在 Spring WebService 中设置 wsa:To:

我需要在 wsa:To 标头中设置一个与扩展 WebServiceGatewaySupport 的客户端不同的值，即端点的 URL。

现在我是这样使用服务的：

public class HelloClient extends WebServiceGatewaySupport {

    public GetHelloResponse getHello(GetHelloRequest request) throws URISyntaxException {
        ActionCallback callback = new ActionCallback(
            new URI("urn","test:mdm:system:epage:b2b:logs:hello",null),new Addressing10()
            );

        return (GetHelloResponse) getwebservicetemplate()
            .marshalSendAndReceive(request,callback);
    }

}

在 Soap 客户端配置类中：

 @Bean
    public HelloClient getHelloClient() throws Exception {
        HelloClient helloClient = new HelloClient();
        helloClient.setMarshaller(getMarshaller());
        helloClient.setUnmarshaller(getMarshaller());
        helloClient.setDefaultUri(env.getProperty("uri.gethelloclient"));
        
        ClientInterceptor[] interceptors = new ClientInterceptor[] {
                securityInterceptor()
        };

        helloClient.setInterceptors(interceptors);

        return helloClient;
    }

在 SOAP Header 中，结果是这样的：

<SOAP-ENV:Header>
  ...
  <wsa:To SOAP-ENV:mustUnderstand="1">http://localhost:8080/ws/hello</wsa:To>
  <wsa:Action>urn:antel:mdm:system:epagos:b2b:comercio:hola</wsa:Action>
  <wsa:MessageID>urn:uuid:27774d62-5867-47ec-b463-f50f702f4ae8</wsa:MessageID>
</SOAP-ENV:Header>

我阅读了官方文档中的 reference，但没有提到这一点。