如何解决Python 3.7 else 语句没有显示正确的索引?
我的目标是将文本文件中的行打印在一起。然而,有些线条并没有像它们应该的那样在一起。我解决了分母在后面的第一个问题。对于 processListObservable
语句,它们似乎都具有相同的值/索引。
else
终端输出:
import fitz # this is pymupdf
with fitz.open("math-problems.pdf") as doc: #below converts pdf to txt
text = ""
for page in doc:
text += page.getText()
file_w = open("output.txt","w") #save as txt file
file_w.write(text)
file_w.close()
file_r = open("output.txt","r") #read txt file
word = 'f(x) = '
#--------------------------
list1 = file_r.readlines() # read each line and put into list
list2 = [k for k in list1 if word in k] # look for all elements with "f(x)" and put all in new list
list1_N = list1
list2_N = list2
list1 = [e[3:] for e in list1] #remove first three characters (the first three characters are always "1) " or "A) "
char = str('\n')
for char in list2:
index = list1.index(char)
def digitcheck(s):
isdigit = str.isdigit
return any(map(isdigit,s))
xx = digitcheck(list1[index])
if xx:
print(list1[index] + " / " + list1_N[index+1])
else:
print(list1[index] + list1[index+1]) # PROBLEM IS HERE,HOW COME EACH VALUE IS SAME HERE?
解决方法
已解决
@copperfield 是正确的,我有重复的值,所以我的索引是重复的。我在 here 中使用 @Shonu93 的解决方案解决了这个问题。本质上,它定位所有重复值的索引,并将这些索引放入一个列表 elem_pos
,然后从 list1
if empty in list1:
counter = 0
elem_pos = []
for i in list1:
if i == empty:
elem_pos.append(counter)
counter = counter + 1
xy = elem_pos
for i in xy:
print(list1[i] + list1_N[i+1])
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