使用注入的 Scala 进行功能测试 playframework 的更好方法是什么

如何解决使用注入的 Scala 进行功能测试 playframework 的更好方法是什么

我使用的是 Scala 2.8，我是 Scala 的新手。由于注入，我在测试此端点时遇到了挑战。

下面是我的端点

@Singleton
class AuthController @Inject()(
                                cc:ControllerComponents,authService: IAuthService
                              )
  extends AbstractController(cc){

  def login() = Action.async { implicit request: Request[AnyContent] =>

    val username:String = request.body.asFormUrlEncoded.flatMap(m => m.get("username").flatMap(_.headOption)).getorElse("")
    val password:String =  request.body.asFormUrlEncoded.flatMap(m => m.get("password").flatMap(_.headOption)).getorElse("")
    val loginRequest = LoginRequest(username,password)

    authService.validate(loginRequest)
      .flatMap{
        case Some(value) => Future.successful(Ok( value.access_token))
        case None => Future.successful(BadRequest("Something went wrong"))
      }
    }

  def register(): Unit ={
    Todo
  }
}

下面是我的测试片段

class AuthControllerTest  extends PlaySpec   {

  "AuthControllerTest" should {
    "login" in {
       val controller = new AuthController(stubControllerComponents(),null)
      val json = Json.parse("{\"firstName\":\"Foo\",\"lastName\":\"Bar\",\"age\":13}")


      val request = FakeRequest(POST,"/v1/auth/login").withJsonBody(json)
      val home = controller.login().apply(request)

      status(home) mustBe OK
    }

    "register" in {

    }
  }
}

解决方法

您可以考虑在测试用例中进行以下更改，这些更改是外观更改

class AuthControllerTest extends PlaySpec with Injecting {
  
  val controller = inject[AuthController]
  
  "AuthControllerTest" should "login" in {
    
      val json = Json.parse(
        """ {
          | "firstName": "Foo",| "lastName": "Bar",| "age": 13
          |}""".stripMargin)


      val request = FakeRequest(POST,"/v1/auth/login").withJsonBody(json)
      val result = call(controller.login(),request)
      status(result) mustBe OK
    }

    "register" in {

    }
  }
}