如何解决如何在 Kivy (Python3) 中动态创建多个函数?
情况
我正在创建一个会议查找器应用程序,它将搜索 JSON 文件并返回多个会议字典的列表。我想为每个会议创建按钮,以便我可以了解有关会议的更多信息或加入会议。由于我需要查询会议列表,所以我不知道会有多少个会议按钮。我需要动态生成和绑定这些按钮。
Python 代码
class Meetingdisplayer(Screen):
def __init__(self,back,info,**kwargs):
super().__init__(**kwargs)
self.back = back
self.info = info # this is the meetings list which contains multiple meeting dictionaries.
self.headings = [] # this will contain the text of the buttons
for meeting in self.info:
meeting_subject = meeting["meeting_subject"]
meeting_organizer = meeting["meeting_organizer"]
time = meeting["time"]
heading = f"{meeting_subject} | {meeting_organizer} | {time}"
self.headings.append([heading,None])
self.scroller = ScrollView()
self.scroller.pos_hint = {"x": 0.1,"top": 0.75}
self.scroller.size_hint = (0.8,0.63)
self.info_grid = GridLayout()
self.info_grid.cols = 1
if len(self.headings) > 20:
self.info_grid.size_hint = 1,2
elif len(self.headings) > 10:
self.info_grid.size_hint = 1,1.4
elif len(self.headings) > 5:
self.info_grid.size_hint = 1,0.8
else:
self.info_grid.size_hint = 1,0.35
i = -1
for heading in self.headings:
i += 1
heading[1] = Button(text = heading[0],font_size = 15,color = (1,1,1),background_color = (0/255,153/255,204/255,on_release = lambda x: self.find_function(i))
self.info_grid.add_widget(heading[1])
self.scroller.add_widget(self.info_grid)
self.add_widget(self.scroller)
def find_function(self,i):
sm.add_widget(Meetinginformation(self.info,name = "Meetinginformation"))
Meetinginformation_screen = sm.get_screen('Meetinginformation')
setattr(Meetinginformation_screen,"index",i)
sm.transition = SlideTransition(direction = "left")
sm.current = "Meetinginformation"
class Meetinginformation(Screen):
def __init__(self,meeting_list,**kwargs):
super().__init__(**kwargs)
self.meeting_list = meeting_list
def on_pre_enter(self):
print(self.index)
meeting = self.meeting_list[self.index]
self.info_grid = GridLayout()
self.info_grid.cols = 2
self.info_grid.size_hint = 0.9,0.4
self.info_grid.pos_hint = {"x": 0.05,"top": 0.67}
self.category_label = Button(text = "Category:",font_size = 14,1))
self.info_grid.add_widget(self.category_label)
self.category_value = Label(text = meeting["category"],color = (0,1))
self.info_grid.add_widget(self.category_value)
self.time_label = Button(text = "Time:",1))
self.info_grid.add_widget(self.time_label)
self.time_value = Label(text = meeting["time"],1))
self.info_grid.add_widget(self.time_value)
self.subject_label = Button(text = "Subject:",1))
self.info_grid.add_widget(self.subject_label)
self.subject_value = Label(text = meeting["meeting_subject"],1))
self.info_grid.add_widget(self.subject_value)
self.organizer_label = Button(text = "Organizer:",1))
self.info_grid.add_widget(self.organizer_label)
self.organizer_value = Label(text = meeting["meeting_organizer"],1))
self.info_grid.add_widget(self.organizer_value)
self.meeting_id_label = Button(text = "Meeting ID:",1))
self.info_grid.add_widget(self.meeting_id_label)
self.meeting_id_value = Label(text = str(meeting["meeting_id"]),1))
self.info_grid.add_widget(self.meeting_id_value)
self.passcode_label = Button(text = str("Meeting Passcode:"),1))
self.info_grid.add_widget(self.passcode_label)
self.passcode_value = Label(text = meeting["passcode"],1))
self.info_grid.add_widget(self.passcode_value)
self.activation_status_label = Button(text = "Activation Status:",1))
self.info_grid.add_widget(self.activation_status_label)
self.activation_status_value = Label(text = str(meeting["active"]),1))
self.info_grid.add_widget(self.activation_status_value)
self.add_widget(self.info_grid)
但问题是当我点击一个按钮时,我只能得到我添加的最后一个按钮小部件。 我的意思是作为索引属性的 i 变量被设置为一个固定数字 [最后一个按钮的索引],它无法识别按下了哪个按钮。
一些可以帮助的图片
after pressing the first button
after pressing the second button
问题
如何动态绑定按钮和函数,让每次按下按钮都能得到那个按钮的准确索引或显示准确信息?
解决方法
尝试改变:
heading[1] = Button(text = heading[0],font_size = 15,color = (1,1,1),background_color = (0/255,153/255,204/255,on_release = lambda x: self.find_function(i))
到:
heading[1] = Button(text = heading[0],on_release = lambda x,j=i: self.find_function(j))
lambda
函数在调用 lambda 时(通过按下按钮)计算 i
。更改为 lambda x,j=i: self.find_function(j)
会在创建 `lambda 时强制对 i
求值。
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