如何过滤 SQLAlchemy 查询以便只返回特定日期中的事件？

如何解决如何过滤 SQLAlchemy 查询以便只返回特定日期中的事件？

我的模型如下所示： 从日期时间导入日期时间，时间增量

 class Contract(db.Model,BaseModel):
    id = Column('id',Integer,primary_key=True)
    client_id = Column(Integer,ForeignKey('client.id'),index=True)
    client = relationship("Client")
    ......
    renewal_date = Column(DateTime)
    
    
 class Client(db.Model,BaseModel):
    id = db.Column('id',db.Integer,primary_key=True)
    name = db.Column(db.String(150))
    ........

因此，我尝试在 sqlAlchemy 中进行查询，如下所示：

def get_renewals_for_client_bymonth(client_id):
    contracts = Contract.query.join(Client) \
                .filter(Client.id == client_id) \
                .order_by(Contract.renewal_date) \    
                .all()

        return contracts    
        
 
 its gives me result something like given below..
 
 data =[
 {  "client": {"id": 3,"name": "zen-zen"},"end_date": "2021-02-02","id": 61,"start_date": "2021-01-03","vendor": "ab"
  },....
  {
    "client": {"id": 3,"name": "zen zen"},"end_date": "2021-04-15","id": 26,"start_date": "2021-02-02","vendor": "test"}
]   
    

按天需要的合约列表：groupby("end_date")
需要输出格式：

list = [
    {"2021-02-02": 
        [
            {
                "client": {"id": 3,"name": "benzene"},"vendor": "ab"
            },{
                "client": {"id": 3,...
            }
        ]
    },{"2021-04-02":
       [
           {
               ...
               "end_date": "2021-04-02","id": 27,.....
           }
       ]
    }
]

我尝试过类似的东西。

filtered = [c for c in contract if (Now + timedelta(days=...)) >= c.end_date]

for k,v in groupby(filtered,key=lambda x: x['end_date']): 返回 {k: list(v)}

我收到错误合同对象不可下标