如何解决如何 fmt Option<String>
我只想在格式表达式中包含一些可选的东西,每次我这样做我最终都会找到一种不同的方式,因为我还没有找到让我满意的方式。
// here's the most basic form,when it works,it's great
let o: Option<&str> = Some("some");
assert_eq!(
format!("format {}",o.unwrap_or_default()),"format some");
// unfortunately,if `o: !copy` that would consume `o`,which I might not want so it becomes a bit longer
let o: Option<String> = Some("some".to_string());
assert_eq!(
format!("format {}",o.as_ref().map(String::as_str).unwrap_or_default()),"format some");
// if I want to get rid of that extra space on `None` then it becomes really ugly
let o: Option<String> = None;
assert_eq!(
format!("format{}",o.as_ref().map(|s| format!(" {}",s)).as_ref().map(String::as_str).unwrap_or_default()),"format");
解决方法
使用 as_deref()
时似乎不会被消耗。
#[derive(Debug)]
struct Thing {
value: i32,}
impl Default for Thing {
fn default() -> Self {
Self { value: -1 }
}
}
impl Default for &Thing {
fn default() -> Self {
&Thing { value: -1 }
}
}
fn main() {
let a: Option<&str> = Some("some &str");
println!("1: {:?}",a.as_deref().unwrap_or_default());
println!("2: {:?}",a);
let b: Option<&str> = None;
println!("1: {:?}",b.as_deref().unwrap_or_default());
println!("2: {:?}",b);
let c: Option<String> = Some("some String".to_owned());
println!("1: {:?}",c.as_deref().unwrap_or_default());
println!("2: {:?}",c);
let d: Option<String> = None;
println!("1: {:?}",d.as_deref().unwrap_or_default());
println!("2: {:?}",d);
let e: Option<Thing> = Some(Thing { value: 123 });
println!("1: {:?}",e.as_ref().as_deref().unwrap_or_default());
println!("2: {:?}",e);
let f: Option<Thing> = None;
println!("1: {:?}",f.as_ref().as_deref().unwrap_or_default());
println!("2: {:?}",f);
}
/*
1: "some &str"
2: Some("some &str")
1: ""
2: None
1: "some String"
2: Some("some String")
1: ""
2: None
1: Thing { value: 123 }
2: Some(Thing { value: 123 })
1: Thing { value: -1 }
2: None
*/
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