如何解决你如何获得数组的索引号而不是元素?
我编写了一个基本程序来查找数组中的最大数并打印它:
#include <stdio.h>
int main(void)
{
int numbers[] = {3,5,12,1,4};
int largest;
largest = numbers[0];
for (int i = 0; i < sizeof(numbers) / sizeof(numbers[0]); i++)
{
if (largest < numbers[i])
{
largest = numbers[i];
}
}
printf("The largest number in the array is %i\n",largest);
}
我需要怎么做,而不是打印 The largest number in the array is 12
,而是打印 The largest number in the array is numbers[2]
?
解决方法
您可以使用索引而不是使用值:
#include <stdio.h>
int main(void)
{
int numbers[] = { 3,5,12,1,4 };
int largest;
largest = 0;
for (int i = 1; i < sizeof(numbers) / sizeof(numbers[0]); i++)
{
if (numbers[largest] < numbers[i])
{
largest = i;
}
}
printf("The largest number in the array is numbers[%d]\n",largest);
return 0;
}
,
一种方法是跟踪索引
#include <stdio.h>
int main(void)
{
int numbers[] = {3,4};
int largest;
int index = 0;
largest = numbers[0];
for (int i = 0; i < sizeof(numbers) / sizeof(numbers[0]); i++)
{
if (largest < numbers[i])
{
largest = numbers[i];
index = i;
}
}
printf("The largest number in the array is %d at numbers[%d]\n",largest,index);
return 0;
}
,
我会这样做:
#include <stdio.h>
int
main(void)
{
int numbers[] = {3,4};
int *largest = numbers;
int *end = numbers + sizeof numbers / sizeof *numbers;
for(int *s = numbers; s < end; s++ ){
if( *s > *largest) {
largest = s;
}
}
printf("The largest number in the array is %d,at position %td\n",*largest,largest - numbers);
}
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