C++ 中的代码跳过了我的第二个字符串 cin 输入

如何解决C++ 中的代码跳过了我的第二个字符串 cin 输入

我在代码中输入第二个字符串时遇到了一些问题。当我第一次这样做时它有效，但是，当我第二次这样做时，它完全跳过它。我第二次复制了代码，但我只是在上面更改了变量名称。有什么想法吗？

第一次很好

string runnerName1;
string runnerName2;

double runTime1 = 0;
double runTime2 = 0;

cout << "First Runner's Name: ";
getline(cin,runnerName1); 
cout << endl;

cout << "Finishing Time: ";
cin >> runTime1;
cout << endl;

然后我添加两个空格并再次执行。然而，它跳过了第二个名字的跑步者名字字符串输入，直接进入完成时间

cout << "Second Runner's Name: ";
getline(cin,runnerName2);
cout << endl;

cout << "Finishing Time: ";
cin >> runTime2;

解决方法

编译器不会忽略 getline()。

它仍在执行并且正在读取 Enter 作为输入。

int main() {
    std::string runnerName1;
    std::string runnerName2;

    double runTime1 = 0;
    double runTime2 = 0;

    std::cout << "First Runner's Name: ";
    std::cin,runnerName1; 
    std::cout << runnerName1 << std::endl;

    std::cout << "Finishing Time1: ";
    std::cin >> runTime1;
    std::cout << runnerName1 << " - " << runTime1  << std::endl;

    std::cout << "Second Runner's Name: ";
    std::cin >> runnerName2; 
    std::cout << runnerName2 << std::endl;

    std::cout << "Finishing Time2: ";
    std::cin >> runTime2; 
    std::cout << runnerName2 << " - " << runTime2  << std::endl;

}

另外一种方式，

std::cin.ignore() （它将丢弃下一个可用字符，因此 换行不再碍事。）

int main() {
    std::string runnerName1;
    std::string runnerName2;

    double runTime1 = 0;
    double runTime2 = 0;

    std::cout << "First Runner's Name: ";
    getline(std::cin.ignore(),runnerName1);  // cin.ignore()

    std::cout << "Finishing Time1: ";
    std::cin >> runTime1;
    std::cout << runnerName1 << " - " << runTime1  << std::endl;

    std::cout << "Second Runner's Name: ";
    getline(std::cin.ignore(),runnerName2); 

    std::cout << "Finishing Time2: ";
    std::cin >> runTime2; 
    std::cout << runnerName2 << " - " << runTime2  << std::endl;
}

示例：Code