如何解决尝试在 dict 中迭代浮点数
我正在尝试完成此功能,但无济于事,因为字典包含我正在尝试总计的浮点值。
这是我目前的代码:
def add_prices(basket):
# Initialize the variable that will be used for the calculation
total = 0
# Iterate through the dictionary items
for groceries,prices in basket.items():
# Add each price to the total calculation
for price in prices:
# Hint: how do you access the values of
# dictionary items?
total += price.values()
# Limit the return value to 2 decimal places
return round(total,2)
groceries = {"bananas": 1.56,"apples": 2.50,"oranges": 0.99,"bread": 4.59,"coffee": 6.99,"milk": 3.39,"eggs": 2.98,"cheese": 5.44}
print(add_prices(groceries)) # Should print 28.44
我完全傻眼了,需要帮助,因为我尝试通过类型转换直接将价格分配给值。任何帮助将不胜感激!
解决方法
您不必遍历 prices
,因为它们已经是 float
值。因此,浮动的错误消息是不可迭代的。
groceries = {"bananas": 1.56,"apples": 2.50,"oranges": 0.99,"bread": 4.59,"coffee": 6.99,"milk": 3.39,"eggs": 2.98,"cheese": 5.44}
def add_prices(basket):
total = 0
for groceries,prices in basket.items():
total += prices
return round(total,2)
add_prices(groceries)
#28.44
正如评论中所提到的,将您的函数更改为单行代码可能更容易,这样您就可以避免 for 循环
def add_prices(basket):
return round(sum(basket.values()),2)
add_prices(groceries)
#28.44
,
您不必要地执行另一个循环。可以直接加价。
阅读dict.keys()
、dict.values()
、dict.items
。
应该是这样
def add_prices(basket):
# Initialize the variable that will be used for the calculation
total = 0
# Iterate through the dictionary items
for groceries,prices in basket.items():
total += prices
# Add each price to the total calculation
#for price in prices:
# Hint: how do you access the values of
# dictionary items?
#total += price.values()
# Limit the return value to 2 decimal places
return round(total,2)
print(add_prices(groceries))
>>> 28.44
,
我不知道你为什么在主循环中做了第二个循环,你可以直接这样做,
def add_prices(basket):
# Initialize the variable that will be used for the calculation
total = 0
# Iterate through the dictionary items
for groceries,prices in basket.items():
total += prices
# Limit the return value to 2 decimal places
return round(total,2)
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