使用 twitter API 的 python 中的 Tweepy/JSONDecodeError 错误

如何解决使用 twitter API 的 python 中的 Tweepy/JSONDecodeError 错误

我试图重现这个例子 [https://github.com/bauyrjanj/NLP-TwitterData/blob/master/TwitterData%20-%20Problem%20Statement%20%26%20Data%20Collection.ipynb]使用带有 'tweepy' 的 twitter 数据，一切都会运行，直到这些代码行：

不知道怎么解决，

谢谢:)

tweets_data_path = 'tweets.txt'
tweets_data=[]
tweets_file_1 = open(tweets_data_path,'r')
# Read in tweets and store in list: tweets_data
for line in tweets_file_1:
    tweet = json.loads(line)
    tweets_data.append(tweet)

# Close connection to file
tweets_file_1.close()

# Print the keys of the first tweet dict
print(tweets_data[0].keys())



JSONDecodeError                           Traceback (most recent call last)
<ipython-input-50-e43cd5de029e> in <module>
      4 # Read in tweets and store in list: tweets_data
      5 for line in tweets_file_1:
----> 6     tweet = json.loads(line)
      7     tweets_data.append(tweet)
      8 

/opt/anaconda3/lib/python3.8/json/__init__.py in loads(s,cls,object_hook,parse_float,parse_int,parse_constant,object_pairs_hook,**kw)
    355             parse_int is None and parse_float is None and
    356             parse_constant is None and object_pairs_hook is None and not kw):
--> 357         return _default_decoder.decode(s)
    358     if cls is None:
    359         cls = JSONDecoder

/opt/anaconda3/lib/python3.8/json/decoder.py in decode(self,s,_w)
    335 
    336         """
--> 337         obj,end = self.raw_decode(s,idx=_w(s,0).end())
    338         end = _w(s,end).end()
    339         if end != len(s):

/opt/anaconda3/lib/python3.8/json/decoder.py in raw_decode(self,idx)
    353             obj,end = self.scan_once(s,idx)
    354         except stopiteration as err:
--> 355             raise JSONDecodeError("Expecting value",err.value) from None
    356         return obj,end

JSONDecodeError: Expecting value: line 1 column 1 (char 0)