如何根据索引位置划分列表？

如何解决如何根据索引位置划分列表？

我有一个由 lat、lon 和 alt 组成的组合列表，如下所示，现在我想将列表分成 3 个部分：lat ，lon 排名第二，alt 排名第三。

coords = [48.92504247289378,9.147973368734435,29707,48.92504291087322,9.147998449546572,48.9250463088055,9.148013780873235,48.92505484289239,9.148021595289876,48.925070689333246,9.148024125370592,29707]

#list format = [lat,lon,alt,lat,alt.....]

异常输出：

lat = [48.92504247289378,48.9250463088055....]
lon = [9.147973368734435,9.148013780873235...]
alt = [29707,...]

我试过了：

Split a python list into other "sublists" i.e smaller lists

Python: Split a list into sub-lists based on index ranges

Split a list into parts based on a set of indexes in Python

还有其他一些解决方案，但都没有奏效。

谁能帮我得到预期的输出？

解决方法

怎么样：

l = [48.92504247289378,9.147973368734435,29707,48.92504291087322,9.147998449546572,48.9250463088055,9.148013780873235,48.92505484289239,9.148021595289876,48.925070689333246,9.148024125370592,29707]
res = [[*l[i::3]] for i in range(3)]

输出是：

>>> res[0]
[48.92504247289378,48.925070689333246]
>>> res[1]
[9.147973368734435,9.148024125370592]
>>> res[2]
[29707,29707]

另一种使用 numpy 的可能解决方案是：

import numpy as np
l_np = np.array(l)
n = 3
res = l_np.reshape(int(l_np.shape[0]/n),n).T

print(res)

array([[4.89250425e+01,4.89250429e+01,4.89250463e+01,4.89250548e+01,4.89250707e+01],[9.14797337e+00,9.14799845e+00,9.14801378e+00,9.14802160e+00,9.14802413e+00],[2.97070000e+04,2.97070000e+04,2.97070000e+04]])

其中 res 矩阵中的每一行都是所需的结果。

,

只需对列表进行切片即可：

coords = [48.92504247289378,29707]
lat = coords[::3]
lon = coords[1::3]
alt = coords[2::3]

,

lat = []
lon = []
alt = []

for i in range(len(coords)):
   if i % 3 == 0:
      lat.append(coords[i])
   elif i % 3 == 1:
      lon.append(coords[i])
   else:
      alt.append(coords[i])