如何解决如何在 Kotlin 中将 JPA 注释放在委托属性上?
@Entity
@Table(name = "plasmid_reference")
class PlasmidReference {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
var id: Int? = null
@Column(name = "project_id")
var projectId: Int? = null
@Column(name = "plasmid_id")
var plasmidId: Int? = null
}
现在,我知道对于 plasmid_reference
连接表中的每个条目none,这些属性都可以为空。 (实际上,数据库强制执行此操作。)
我如何告诉 Kotlin?
一种天真的方法是尝试使用 lateinit
...
@Entity
@Table(name = "plasmid_reference")
class PlasmidReference {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
lateinit var id: Int
@Column(name = "project_id")
lateinit var projectId: Int
@Column(name = "plasmid_id")
lateinit var plasmidId: Int
}
这甚至无法编译。
基本类型的属性不允许使用'lateinit'修饰符
好的,让我们采用建议的解决方案并转换为使用委托。
@Entity
@Table(name = "plasmid_reference")
class PlasmidReference {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
var id by notNull<Int>()
@Column(name = "project_id")
var projectId by notNull<Int>()
@Column(name = "plasmid_id")
var plasmidId by notNull<Int>()
}
这仍然无法编译,因为
此注解不适用于目标'member property with delegate'
好吧……这听起来像是 kotlin 的事情,在 Java 中,我会在字段上扔注释,所以也许……
@Entity
@Table(name = "plasmid_reference")
class PlasmidReference {
@field:Id
@field:GeneratedValue(strategy = GenerationType.IDENTITY)
var id by notNull<Int>()
@field:Column(name = "project_id")
var projectId by notNull<Int>()
@field:Column(name = "plasmid_id")
var plasmidId by notNull<Int>()
}
不,事实证明,并非如此。仍然无法编译,因为
好的,让我们注释“存储委托属性的委托实例的字段”(参见 https://kotlinlang.org/docs/reference/annotations.html#annotation-use-site-targets )
@Entity
@Table(name = "plasmid_reference")
class PlasmidReference {
@delegate:Id
@delegate:GeneratedValue(strategy = GenerationType.IDENTITY)
var id by notNull<Int>()
@delegate:Column(name = "project_id")
var projectId by notNull<Int>()
@delegate:Column(name = "plasmid_id")
var plasmidId by notNull<Int>()
}
这确实可以编译但会抛出运行时异常,因为
The attribute [plasmidId] is not present in the managed type [EntityTypeImpl@960932033:PlasmidReference
[ javaType: class com.[...].PlasmidReference descriptor: RelationalDescriptor(com.[...].PlasmidReference --> [DatabaseTable(plasmid_reference)]),mappings: 3]].
at org.eclipse.persistence.internal.jpa.metamodel.ManagedTypeImpl.getAttribute(ManagedTypeImpl.java:151)
at org.springframework.data.jpa.repository.query.QueryUtils.toExpressionRecursively(QueryUtils.java:635)
Aaaaa我没有想法了。
我该如何解决这个问题?
解决方法
将其移动到构造函数定义应该可以解决问题
@Entity
@Table(name = "plasmid_reference")
class PlasmidReference(
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
var id: Int? = null,@Column(name = "project_id")
var projectId: Int,@Column(name = "plasmid_id")
var plasmidId: Int
)
版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。