如何解决如何删除字符串中的空格和行?
这就是我所拥有的
S = """Missing Since 06/01/1976
Missing From
Napa,California
Classification Endangered Missing
Sex Female
Race
White
Date of Birth 02/06/1957 (63)
Age 19 years old
Height and Weight 5'2,130 pounds
Distinguishing Characteristics Caucasian female. Brown hair,hazel eyes."""
我想去的地方
S = """Missing Since 06/01/1976
Missing From Napa,California
Classification Endangered Missing
Sex Female
Race White
Date of Birth 02/06/1957 (63)
Age 19 years old
Height and Weight 5'2,hazel eyes."""
我尝试使用 S.strip()
,但只删除了开头和结尾的空格。
我想知道是否有任何可行的实现(我找不到任何实现)。
我也尝试将 S.replace(" ","")
用于更大的空间,但这也让我无处可去。
解决方法
删除多个空格(不是行):
print( ' '.join([s for s in S.split(' ') if s.strip()]) )
,
试试这个:
import re
def normalize_text(get_text):
saved_new_lines = []
counter = 0
for each_line in get_text.split("\n"):
if not each_line == "":
normalize_each_line = re.sub(r'\s+',' ',each_line.strip())
if each_line.startswith(" "):
saved_new_lines[counter-1] += " " + normalize_each_line
else:
saved_new_lines.append(normalize_each_line)
counter += 1
return "\n".join(saved_new_lines)
print(normalize_text(S))
输出:
Missing Since 06/01/1976
Missing From Napa,California
Classification Endangered Missing
Sex Female
Race White
Date of Birth 02/06/1957 (63)
Age 19 years old
Height and Weight 5'2,130 pounds
Distinguishing Characteristics Caucasian female. Brown hair,hazel eyes.
@FedericoBaù 给了我提示;所以我更新了我的代码(这个版本没有任何空行检查器,所以它会比当前状态快得多)
更新:
import re
def normalize_text(get_text):
saved_new_lines = []
counter = 0
for each_line in re.sub(r'\n+','\n',get_text.strip()).splitlines():
normalize_each_line = re.sub(r'\s+',each_line.strip())
if each_line.startswith(" "):
saved_new_lines[counter-1] += " {}".format(normalize_each_line)
else:
saved_new_lines.append(normalize_each_line)
counter += 1
return "\n".join(saved_new_lines)
print(normalize_text(test_string))
,
这是一种仅使用字符串文字输入生成请求的字符串文字输出的方法,如(最初)请求的那样:
from re import sub
print(sub('Race\n','Race ',sub('Missing From\n','Missing From ','\n'.join(
[sub(' \s','',line) for line in [line.strip() for line in """
"Missing Since 06/01/1976
Missing From
Napa,California
Classification Endangered Missing
Sex Female
Race
White
Date of Birth 02/06/1957 (63)
Age 19 years old
Height and Weight 5'2,hazel eyes."
""".split('\n') if line.strip()]]))))
输出:
"Missing Since 06/01/1976
Missing From Napa,hazel eyes."
,
我不喜欢 python 但据我所知在 php 中这些空格是由于 \n
和 \r
而出现的,要修复,您可以简单地执行 string.replace("<double-space-here>","")
然后获取变量并重做过程,但这次替换“\n”然后“\r”。如果你能找到一个内置的方法来过滤 python 中的 html 字符,我会更好。
@Random 尽管已经提供了非常有用的答案,但我想就您所面临的问题提供更多见解,这很常见,尤其是因为函数 strip
的期望是如何。
从逻辑上讲,人们可能认为它应该删除字符串中的所有项目,但它只删除了字符串的 2 端,而不是字符串的“内部”,但为什么呢?
您应该首先了解字符串 a 是如何真正存储在 Python 中的,例如它们实际上就像“数组”(一种列表):
string = " Hello world "
实际上是:
string = [" "," ","H",'e','l','o','w','r','d',' ']
所以 strip 函数去检查它从字符串的左边和右边找到的任何字符,然后停止直到遇到不同的字符。
因此它不会在整个字符串(数组)上循环,而只会从索引 0 或索引 -1 开始!
有关这方面的更多信息,我建议查看 array-of-strings-in-c,尽管不是 Python,但 Python 是用 C 编写的并且内部具有相同的实现。
一些解决方案(尚未给出)
-
import string def string_cleaner(str): cleaned_string = [] string_separated = str.split(' ') for word in string_separated: if word: if word in string.whitespace: del word else: cleaned_string.append(word) ready_baby = ' '.join(cleaned_string) return ready_baby result = string_cleaner(test_string)
--> 使用列表推导式的简短形式
print(' '.join([s for s in test_string.split(' ') if s and s not in string.whitespace]))
-
使用函数 isspace(无需导入,纯内置)
def string_cleaner(str): cleaned_string = [] string_separated = str.split(' ') for word in string_separated: if word: if word.isspace(): del word else: cleaned_string.append(word) ready_baby = ' '.join(cleaned_string) return ready_baby result = string_cleaner(test_string) print(result)
--> 使用列表推导式的简短形式
print(' '.join([string for string in test_string.split(' ') if string and not string.isspace()]))
重新访问re.sub函数
这里是 re.sub
所做的复制,请注意,我添加了许多“无用”变量以使代码更加明确:
def string_cleaner(str):
cleaned_string = []
string_separated = str.split(' ')
for word in string_separated:
if word: # Not Blank line
remove_whitespace_from_side = word.strip().replace('\n',' ') # NOTE: we do this because there are multiple \n\n in some string
separate_each_string = remove_whitespace_from_side.split()
if separate_each_string: # NOTE: If empty means that is a useless white spece within a string
rejoined_sub_string = ' '.join(separate_each_string)
ready_string = rejoined_sub_string.replace(' ','\n') # Add again \n
cleaned_string.append(ready_string)
ready_to_go = ' '.join(cleaned_string)
return ready_to_go
result = string_cleaner(test_string)
print(result)
文档
“返回通过替换 repl 替换 string 中最左边的非重叠模式所获得的字符串。”。
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