如何解决我如何定义函数以使用 python 集成列表?
我正在尝试定义一个遍历三种列表列表的函数,每个列表具有以下结构:
sentiment_labels = [['B_S','O','O'],['O','B_S','O']]
aspect_labels = [['O','B_A','B_A']]
modifier_labels = [['O','BM','O']]
# those lists contain 'B_A','I_S','IM',and 'O' labels (IOB Tagging)
目标结果必须是这样的:
labels = [['B_S','B_A'] ]
为此,我定义了以下函数:
# define function to integrate sentiments,aspects,and modifiers lists
def integrate_labels(sentiments_lists,aspects_lists,modifiers_lists):
all_labels = []
integrated_label = []
# iterate through each list,then iterate through each element
for sentiment_list,aspect_list,modifier_list in zip(sentiments_lists,modifiers_lists):
for sentiment,aspect,modifier in zip(sentiment_list,modifier_list):
# if the element is a sentiment label append it to the integrated_label list
if sentiment != 'O':
integrated_label.append(sentiment)
# if the element is an aspect label append it to the integrated_label list
elif aspect != 'O':
integrated_label.append(aspect)
# if the element is a modifier label append it to the integrated_label list
elif modifier != 'O':
integrated_label.append(modifier)
else:
integrated_label.append('O')
# now append each integrated_label list to all_labels list
all_labels.append(integrated_label)
return all_labels
但我有这个结果:
integrate_labels(sentiment_labels,aspect_labels,modifier_labels)
[['B_S','B_A'],['B_S','B_A']]
如何更改integrate_labels 函数以获得目标结果?
提前致谢!
解决方法
改为
# now append each integrated_label list to all_labels list
all_labels.append(integrated_label.copy())
integrated_label = []
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