如何在父查询 case 语句中使用子查询的结果

如何解决如何在父查询 case 语句中使用子查询的结果

我有以下查询返回预期结果：

SELECT
    locations.*,(
        SELECT
            id
        FROM
            hauls
        WHERE
            haul_type_id = 1
            AND location_id = locations.id
        ORDER BY
            created_at DESC
        LIMIT 1) AS last_delivery_id,(
        SELECT
            id
        FROM
            hauls
        WHERE
            haul_type_id = 2
            AND location_id = locations.id
        ORDER BY
            created_at DESC
        LIMIT 1) AS last_pickup_id
FROM
    locations

我想在父查询的 case 语句中使用子查询 (last_delivery_id,last_pickup_id) 的结果，但出现错误：

错误：未知列“last_delivery_id”

SELECT
    locations.*,case when last_delivery_id = 1 then 'pending' when last_delivery_id = 2 then 'active' end as status,(
        SELECT
            id
        FROM
            hauls
        WHERE
            haul_type_id = 2
            AND location_id = locations.id
        ORDER BY
            created_at DESC
        LIMIT 1) AS last_pickup_id
FROM
    locations

解决方法

您可以使用子查询或 CTE：

SELECT lh.*,. . .   -- any expressions you want
       (case when last_delivery_id = 1 then 'pending'
             when last_delivery_id = 2 then 'active'
        end) as status
FROM (SELECT l.*,(SELECT id
              FROM hauls h
              WHERE h.haul_type_id = 1 AND
                    h.location_id = l.id
              ORDER BY h.h.created_at DESC
              LIMIT 1
             ) AS last_delivery_id,(SELECT id
              FROM hauls h
              WHERE h.haul_type_id = 2 AND
                    h.location_id = l.id
              ORDER BY h.created_at DESC
              LIMIT 1
             ) AS last_pickup_id
      FROM locations l
     ) lh

请注意表别名的使用，这使查询更易于编写和阅读。也就是说，如果您只想要字符串版本，我不确定您是否真的需要 delivery_id：

      SELECT l.*,(SELECT (case when h.id = 1 then 'pending'
                           when h.id = 2 then 'active'
                      end)
              FROM hauls h
              WHERE h.haul_type_id = 1 AND
                    h.location_id = l.id
              ORDER BY h.created_at DESC
              LIMIT 1
             ) AS status
      FROM locations l

,

考虑用 CTE 和窗口函数重写内联子查询。这避免了使用 LIMIT 子句，如果没有以最佳方式运行，它可以具有 performance issues。这需要支持 CTE 和窗口函数的 MySQL 8.0+ 版本：

WITH sub AS (
  SELECT id AS last_delivery_id,location_id,haul_type_id,ROW_NUMBER() OVER (PARTITION BY location_id,haul_type_id
                            ORDER BY created_at DESC) AS rn
  FROM hauls
)

SELECT l.*       -- CONSIDER EXPLICITLY SELECTING COLUMNS FOR PERFORMANCE,CASE
          WHEN h1.last_delivery_id = 1 THEN 'pending' 
          WHEN h2.last_delivery_id = 2 THEN 'active' 
       END AS `status`
FROM locations l
LEFT JOIN sub h1
  ON h1.location_id = l.id
 AND h1.haul_type_id = 1
 AND h1.rn = 1
LEFT JOIN sub h2
  ON h2.location_id = l.id
 AND h2.haul_type_id = 2
 AND h2.rn = 1

对于早期版本（

SELECT l.*       -- CONSIDER EXPLICITLY SELECTING COLUMNS FOR PERFORMANCE,CASE
          WHEN h1.id = 1 THEN 'pending' 
          WHEN h2.id = 2 THEN 'active' 
       END AS `status`
FROM locations l
LEFT JOIN
    (SELECT location_id,MAX(CASE WHEN haul_type_id = 1 THEN created_at END) AS h1_max_date,MAX(CASE WHEN haul_type_id = 2 THEN created_at END) AS h2_max_date
     FROM hauls
     GROUP BY location_id
    ) h_agg
   ON l.location_id = h_agg.location_id
LEFT JOIN hauls h1
   ON  h1.location_id = h_agg.location_id
   AND h1.haul_type_id = 1
   AND h1.created_at = h_agg.h1_max_date
LEFT JOIN hauls h2
   ON  h2.location_id = h_agg.location_id
   AND h2.haul_type_id = 2
   AND h2.created_at = h_agg.h2_max_date

,

如果您运行的是 MySQL 8.0.14 或更高版本，您可以为此使用横向连接：

select l.*,h1.*,h2.*
    case 
        when last_delivery_id = 1 then 'pending' 
        when last_delivery_id = 2 then 'active' 
    end as status
from locations l
left join lateral (
    select h.id as last_delivery_id
    from hauls h
    where h.haul_type_id = 1 and h.location_id = l.id
    order by h.created_at desc limit 1
) h1 on true
left join lateral (
    select h.id as last_pickup_id
    from hauls h
    where h.haul_type_id = 2 and h.location_id = l.id
    order by h.created_at desc limit 1
) h2 on true

横向连接是一个强大的特性，MySQL 已经缺失了很长时间。例如，上面的语句可以很容易地适应从每个子查询返回更多的列。

,

因为 select 部分中的所有列都一次执行，而 last_delivery_id 列尚未创建，您尝试使用它，sql server 返回错误，为了解决它，您可以使用 CTE ，视图和驱动表。