如何迭代 2 个 JSON 列表混合字典和列表，匹配特定值并打印另一个值

如何解决如何迭代 2 个 JSON 列表混合字典和列表，匹配特定值并打印另一个值

我有 2 个单独的 JSON 列表（带有字典）。 我的目标是，我想遍历 list2“currentUser”，获取值，在 list1 中搜索这些值，并作为输出打印“firstName”的值

例如 liste2：“当前用户”：123， liste1: "id": "123",--> "firstName": "Lisa",

list1 = {
    "X-API-KEY": "XyZzahZaksksXXXYYYOOO000","user": {
                "email": "[e-mail]","firstName": "Lisa","id": "123",},"Flat": {
        "city": "Munich","country": "2","countryCode": "DEU","currency": "EUR","date": "1587671397","flatmates": [
            {
                "email": "[e-mail]",{
                "email": "[e-mail]","firstName": "Max","id": "124",{
                "email": "[e-mail]","firstName": "Hannah","id": "125",{
                "email": "[e-mail]","firstName": "Kai","id": "126",}
        ],"founderId": "123","id": "99999","image": "","name": "ABC","postCode": "000000",}
}

list2 = [
    {
        "creationDate": 1587671663,"currentUser": 123,"id": 1717134,"title": "Do this","users": [
            124,126
        ]
    },{
        "creationDate": 1587671663,"currentUser": 126,"title": "Do that","users": [
            123,125
        ]
    },{
        "creationDate": 1587671821,"currentUser": 124,"title": "Clean this","users": [
            125,122
        ]
    },{
        "creationDate": 1587671801,"title": "Clean that",126
        ]
    }
]

我对 python 很陌生。 对我来说有几个头脑问题，因为其中混合了列表和字典，以及如何匹配/搜索 2 个单独的列表/字典的值

到目前为止我得到了什么：迭代“CurrentUser”

for user in liste2:
    print(user["currentUser"])

有人有办法吗？

解决方法

在没有其他模块的纯 python 中。

for user in list2:
    for mate in list1['Flat']['flatmates']:
        if user['currentUser'] == int(mate['id']):
            # You found the person now execute this code...

需要注意的一点是，在您的 list1 中，您的室友 id 不是整数，而是字符串。因此，您必须将其转换为 int 才能比较两者。