如何解决输入中出现意外字符:<b>/homepages/1/d835516322/htdocs/vitruvium/first.php</b> 中的 '\' (ASCII=92) state=1 <b>8</b><br />
我有这个 PayPal 文档文件,我需要通过命令行运行它,一切看起来都很好,但我遇到了一些麻烦。 任何线索发生了什么以及如何解决它?我读了一些关于 windows 的 \r\n 并将其转换为 \n,但我不确定它是什么意思。
<?PHP
// 1. Autoload the SDK Package. This will include all the files and classes to your autoloader
require __DIR__ . '/PayPal-PHP-SDK/autoload.PHP';
// 2. Provide your Secret Key. Replace the given one with your app clientId,and Secret
// https://developer.paypal.com/webapps/developer/applications/myapps
$apiContext = new \PayPal\Rest\ApiContext(
new \PayPal\Auth\OAuthTokenCredential(
'my CLient id',// ClientID
'My client secret' // ClientSecret
)
);
// 3. Lets try to create a Payment
// https://developer.paypal.com/docs/api/payments/#payment_create
$payer = new \PayPal\Api\Payer();
$payer->setPaymentMethod('paypal');
$amount = new \PayPal\Api\Amount();
$amount->setTotal('1.00');
$amount->setCurrency('USD');
$transaction = new \PayPal\Api\Transaction();
$transaction->setAmount($amount);
$redirectUrls = new \PayPal\Api\RedirectUrls();
$redirectUrls->setReturnUrl("https://neovinci.es/success.html")
->setCancelUrl("https://neovinci.es/cancel.html");
$payment = new \PayPal\Api\Payment();
$payment->setIntent('sale')
->setPayer($payer)
->setTransactions(array($transaction))
->setRedirectUrls($redirectUrls);
// 4. Make a Create Call and print the values
try {
$payment->create($apiContext);
echo $payment;
echo "\n\nRedirect user to approval_url: " . $payment->getApprovalLink() . "\n";
}
catch (\PayPal\Exception\PayPalConnectionException $ex) {
// This will print the detailed information on the exception.
//REALLY HELPFUL FOR DEBUGGING
echo $ex->getData();
}
但是当我从命令行运行它时总是出现这些错误:
<b>Warning</b>: Unexpected character in input: '\' (ASCII=92) state=1 in <b>/homepages/1/d835516322/htdocs/vitruvium/first.PHP</b> on line <b>8</b><br />
和
<b>Parse error</b>: Syntax error,unexpected T_STRING in <b>/homepages/1/d835516322/htdocs/vitruvium/first.PHP</b> on line <b>8</b><br />
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