如何解决我如何优化这个简单的 python pygame 代码
我面临着使用 pygame 制作游戏的挑战(我正在制作蛇,所以它应该很容易......但我从未使用过 pygame)所以使用更高效的语言不是一种选择。所以我的问题是我更新蛇网格太慢了,而且我在 pygame 中没有足够的经验来解决这个问题,任何人都可以提供帮助。另外作为一个说明,如果我只填充网格,它不会在蛇后面清除。 使用 python 3.8
import pygame
import time
import random
pygame.init()
display_width = 800
display_height = 600
display = pygame.display.set_mode((display_width,display_height))
pygame.display.set_caption("Snake")
pureblue = (0,255)
purered = (255,0)
puregreen = (0,255,0)
white = (255,255)
black = (1,1,1)
grey = (50,50,50)
darkgrey = (25,25,25)
clock = pygame.time.Clock()
snake_block = 10
snake_speed = 30
font_style = pygame.font.SysFont(None,50)
def drawGrid():
blockSize = 10
for x in range(display_width):
for y in range(display_height):
rect = pygame.Rect(x*blockSize,y*blockSize,blockSize,blockSize)
pygame.draw.rect(display,darkgrey,rect,1)
def message(msg,colour):
text = font_style.render(msg,True,colour)
display.blit(text,[display_width/2,display_height/2])
def SnakeGameLoop():
game_over = False
X = display_width/2
Y = display_height/2
X_change = 0
Y_change = 0
while not game_over:
for event in pygame.event.get():
if event.type == pygame.QUIT:
game_over = True
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_LEFT:
X_change = -10
Y_change = 0
elif event.key == pygame.K_RIGHT:
X_change = 10
Y_change = 0
elif event.key == pygame.K_UP:
X_change = 0
Y_change = -10
elif event.key == pygame.K_DOWN:
X_change = 0
Y_change = 10
if X >= display_width or X < 0 or Y >= display_height or Y < 0:
game_over = True
X += X_change
Y += Y_change
display.fill(grey)
drawGrid()
pygame.draw.rect(display,puregreen,[X,Y,10,10])
pygame.display.update()
clock.tick(15)
message("You lost",purered)
pygame.display.update()
time.sleep(2)
pygame.quit()
quit()
SnakeGameLoop()
解决方法
为了提高游戏的性能,在应用程序循环之前在pygame.Surface
对象上绘制与屏幕大小相同的网格:
def drawGrid(surf):
surf.fill(grey)
blockSize = 10
for x in range(display_width):
for y in range(display_height):
rect = pygame.Rect(x*blockSize,y*blockSize,blockSize,blockSize)
pygame.draw.rect(surf,darkgrey,rect,1)
grid_surf = pygame.Surface(display.get_size())
drawGrid(grid_surf)
blit
在显示器上每帧绘制一次表面而不是每帧绘制一次网格,在应用程序循环中:
def SnakeGameLoop():
# [...]
while not game_over:
# [...]
display.blit(grid_surf,(0,0))
pygame.draw.rect(display,puregreen,[X,Y,10,10])
pygame.display.update()
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