如何解决如何使用排球赞美多个YouTube频道
我正在为所有客户的youtube频道创建一个应用程序,我在用凌空抽奖来赞美这些频道,
我的问题是,当我单击任何一个频道时,它只能检索一个频道,因此如何使凌空区了解到它应该在点击时获取不同的频道
这是代码示例>
ListView channelList;
ArrayList<VideoDetails> videoDetailsArrayList;
ChannelAdapter channelAdapter;
String channelUrl="";
String channelId;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_channel);
channelList = findViewById(R.id.channelList);
videoDetailsArrayList = new ArrayList<>();
channelAdapter = new ChannelAdapter(ChannelActivity.this,videoDetailsArrayList);
channelUrl = String.format(getIntent().getStringExtra("channelUrl"),channelId);
channelId = getIntent().getStringExtra("id");
displayVideos();
}
private void displayVideos() {
RequestQueue requestQueue = Volley.newRequestQueue(getApplicationContext());
StringRequest stringRequest = new StringRequest(Request.Method.GET,channelUrl,new Response.Listener<String>() {
@Override
public void onResponse(String response) {
try {
JSONObject jsonObject = new JSONObject(response);
JSONArray jsonArray = jsonObject.getJSONArray("items");
for(int i=0;i<jsonArray.length();i++){
JSONObject jsonObject1 = jsonArray.getJSONObject(i);
JSONObject jsonVideoId = jsonObject1.getJSONObject("id");
JSONObject jsonObjectSnippet = jsonObject1.getJSONObject("snippet");
JSONObject jsonObjectDefault = jsonObjectSnippet.getJSONObject("thumbnails").getJSONObject("medium");
String video_Id = jsonVideoId.getString("videoId");
VideoDetails vd = new VideoDetails();
vd.setVideoId(video_Id);
vd.setTitle(jsonObjectSnippet.getString("title"));
vd.setDescription(jsonObjectSnippet.getString("description"));
vd.setUrl(jsonObjectDefault.getString("url"));
videoDetailsArrayList.add(vd);
}
channelList.setAdapter(channelAdapter);
channelAdapter.notifyDataSetChanged();
}catch (JSONException e)
{
e.printstacktrace();
}
}
},new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Toast.makeText(getApplicationContext(),error.getMessage(),Toast.LENGTH_LONG).show();
}
}
);
requestQueue.add(stringRequest);
}
}
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