如何解决如何在Android中通过凌空调用API带有键?
我正在尝试构建一个用于搜索餐厅及其菜式的应用程序。为此,我使用了Zomato API。下面是调用zomato API(带有密钥)的代码:-
String URL="https://developers.zomato.com/api/v2.1/search";
private void extractData(){
RequestQueue requestQueue= Volley.newRequestQueue(Search.this);
JsonArrayRequest objectRequest = new JsonArrayRequest(
Request.Method.GET,URL,null,new Response.Listener<JSONArray>() {
@Override
public void onResponse(final JSONArray response) {
Toast.makeText(Search.this,"Response",Toast.LENGTH_LONG).show();
for(int i=0; i<response.length();i++){
try{
JSONObject foodobject= response.getJSONObject(i);
Food food= new Food();
food.setResname(foodobject.getString("name").toString());
foods.add(food);
}
catch(JSONException e){
e.printstacktrace();
}
}
recyclerView.setLayoutManager(new linearlayoutmanager(getApplicationContext()));
adapter= new com.example.street99.Adapter(getApplicationContext(),foods);
recyclerView.setAdapter(adapter);
}
},new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Toast.makeText(Search.this,"Failed",Toast.LENGTH_LONG).show();
}
}
){
public Map<String,String> getHeaders() throws AuthFailureError
{
Map<String,String> headers = new HashMap();
headers.put("user-key","40696d75dc6b76cd7687f1838f70a24d");
return headers;
}
public Map getParams()
{
Map params = new HashMap();
params.put("q",q);
return params;
}
};
requestQueue.add(objectRequest);
}
}
但是每次我收到消息失败。有人可以帮我吗?
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