如何解决在Julia 1.5.2上使用animation.py时出错
我使用this link的第一个示例制作视频。在我更换计算机之前的Julia版本中,我认为版本1.2可以正常工作。 现在,一切正常,直到最后一行
myanim[:save]("testvid.mp4",writer=mywriter)
我收到错误消息的地方:
ERROR: PyError ($(Expr(:escape,:(ccall(#= /Users/XX/.julia/packages/PyCall/BcTLp/src/pyfncall.jl:43 =# @pysym(:PyObject_Call),PyPtr,(PyPtr,PyPtr),o,pyargsptr,kw))))) <class 'FileNotFoundError'>
FileNotFoundError(2,'No such file or directory')
File "/Users/XX/.julia/conda/3/lib/python3.8/site-packages/matplotlib/animation.py",line 1123,in save
with mpl.rc_context({'savefig.bBox': None}),\
File "/Users/XX/.julia/conda/3/lib/python3.8/contextlib.py",line 113,in __enter__
return next(self.gen)
File "/Users/XX/.julia/conda/3/lib/python3.8/site-packages/matplotlib/animation.py",line 249,in saving
self.setup(fig,outfile,dpi,*args,**kwargs)
File "/Users/XX/.julia/conda/3/lib/python3.8/site-packages/matplotlib/animation.py",line 338,in setup
self._run()
File "/Users/XX/.julia/conda/3/lib/python3.8/site-packages/matplotlib/animation.py",line 348,in _run
self._proc = subprocess.Popen(
File "/Users/XX/.julia/conda/3/lib/python3.8/subprocess.py",line 854,in __init__
self._execute_child(args,executable,preexec_fn,close_fds,File "/Users/XX/.julia/conda/3/lib/python3.8/subprocess.py",line 1702,in _execute_child
raise child_exception_type(errno_num,err_msg,err_filename)
Stacktrace:
[1] pyerr_check at /Users/XX/.julia/packages/PyCall/BcTLp/src/exception.jl:62 [inlined]
[2] pyerr_check at /Users/XX/.julia/packages/PyCall/BcTLp/src/exception.jl:66 [inlined]
[3] _handle_error(::String) at /Users/XX/.julia/packages/PyCall/BcTLp/src/exception.jl:83
[4] macro expansion at /Users/XX/.julia/packages/PyCall/BcTLp/src/exception.jl:97 [inlined]
[5] #110 at /Users/XX/.julia/packages/PyCall/BcTLp/src/pyfncall.jl:43 [inlined]
[6] disable_sigint at ./c.jl:446 [inlined]
[7] __pycall! at /Users/XX/.julia/packages/PyCall/BcTLp/src/pyfncall.jl:42 [inlined]
[8] _pycall!(::PyObject,::PyObject,::Tuple{String},::Int64,::PyObject) at /Users/XX/.julia/packages/PyCall/BcTLp/src/pyfncall.jl:29
[9] _pycall!(::PyObject,::Base.Iterators.Pairs{Symbol,PyObject,Tuple{Symbol},NamedTuple{(:writer,),Tuple{PyObject}}}) at /Users/XX/.julia/packages/PyCall/BcTLp/src/pyfncall.jl:11
[10] #_#117 at /Users/XX/.julia/packages/PyCall/BcTLp/src/pyfncall.jl:86 [inlined]
[11] top-level scope at REPL[137]:1
有人知道发生了什么事吗?
完全相同的代码在以前的Julia版本中运行得很好。
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