如何解决Java中的Pacman碰撞
我正在用Java开发一个pacman街机游戏,但是我的碰撞有问题。 如果看到我的形象 here我的吃豆精灵在走到拐角处或试图转回其出现的方向时(即向左走但不再向右走)静止不动(无x或y运动)。我了解这是因为,如果检测到冲突,我会将xMovement设置为0,将yMovement设置为0(请参见collide()下的第二个代码块)。
如果我的crash()不允许这样做,我该如何允许pacman精灵以另一种方式移动(即它来自左侧,我希望它向右移动)或越过一个角落?
下面是App.java类中的draw方法,该方法根据用户的输入绘制播放器。按键分别对应于上,左,下,右。仅使用this.direction,以便在发生碰撞时玩家不会浪费任何举动,也不会穿过墙。 *请注意,我放(this.player.x_ord + 2) % 16 == 0
是因为我的吃豆人图像不是16x16图像,这与我的墙壁不同。
public void draw() { // This is an infinite loop
mapDraw(); // this draws my map constantly so I do not have multiple pacman sprites drawn
this.player.tick(); // see second code below for details
if (keypressed){ // Used wasd rather than arrow keys
if (key == 's' && this.direction != 's' && (this.player.x_ord + 2) % 16 == 0 &&
(this.player.y_ord + 4) % 16 == 0){ // We dont want Player to turn ever on a non 16 divisible area
this.player.p = this.loadImage("src/main/resources/playerDown.png");
this.player.yMovement = this.player.speed;
this.player.xMovement = 0;
this.direction = 's';
}
else if (key == 'w' && this.direction != 'w' && (this.player.x_ord + 2) % 16 == 0 &&
(this.player.y_ord + 4) % 16 == 0){
this.player.p = this.loadImage("src/main/resources/playerUp.png");
this.player.yMovement = -this.player.speed;
this.player.xMovement = 0; // I do not want my pacman to move diagonally so thats why
this.direction = 'w';
}
else if (key == 'd' && this.direction != 'd' && (this.player.x_ord + 2) % 16 == 0 &&
(this.player.y_ord + 4) % 16 == 0){
this.player.p = this.loadImage("src/main/resources/playerRight.png");
this.player.xMovement = this.player.speed;
this.player.yMovement = 0;
this.direction = 'd';
}
else if (key == 'a' && this.direction != 'a' && (this.player.x_ord + 2) % 16 == 0 &&
(this.player.y_ord + 4) % 16 == 0){
this.player.p = this.loadImage("src/main/resources/playerLeft.png");
this.player.xMovement = -this.player.speed;
this.player.yMovement = 0;
this.direction = 'a';
}
}
this.player.draw(this); //see second code below for details
}
下面是我的player.java类
*请再次注意,this.x_ord + 2 == w.x_pos + 16 && this.y_ord + 4 == w.y_pos
因为我的吃豆精灵精灵大于我的16x16墙壁而偏移了。
public void tick(){
// //logic
this.detectCollision();
if (this.isLiving){
this.y_ord += this.yMovement;
this.x_ord += this.xMovement;
}
}
public void draw(papplet a){ //just draw the sprite
if (this.isLiving){
a.image(this.p,this.x_ord,this.y_ord);
}
}
public void collide(boolean isX){ // Is it an x or y collision
if (isX == true){ // If it moves left or right into a wall
this.xMovement = 0;
}
else if (isX == false){ // If it moves up or down into a wall
this.xMovement = 0;
}
}
public void detectCollision(){
for (Walls w: this.wallLocations){ // A list of wall locations from a .txt file
if (this.x_ord + 2 == w.x_pos + 16 && this.y_ord + 4 == w.y_pos){ // Detect left movement into right wall piece
collide(true);
}
if (this.x_ord + 2 + 16 == w.x_pos && this.y_ord + 4 == w.y_pos){ // Detect right movement into left wall piece
collide(true);
}
if (this.y_ord + 4 == w.y_pos + 16 && this.x_ord + 2 == w.x_pos){ // Detect up movement into bottom wall piece
collide(false);
}
if (this.y_ord + 4 + 16 == w.y_pos && this.x_ord + 2 == w.x_pos){ // Detect down movement into top wall piece
collide(false);
}
}
对于我的问题的任何帮助,我们深表感谢。
解决方法
我没有深入分析您的代码,但是在我看来,您的主要问题是collide
方法仅考虑2种情况,即垂直移动或水平移动。如果要在4个不同的方向上移动,则该方法需要具有4个不同的状态。
为此,您可以创建一个代表方向的枚举。然后在detectCollision
中将适当的Direction
传递到collide
中。最后,在collide
中考虑4个不同的方向。例如,如果右侧有障碍,则xMovement
必须为非正数。 collide
方法看起来像这样:
public void collide(Direction direction){
if (direction == Direction.RIGHT){
this.xMovement = Math.min(0,this.xMovement);
}
if (direction == Direction.LEFT){
this.xMovement = Math.max(0,this.xMovement);
}
if (direction == Direction.UP){
this.yMovement = Math.min(0,this.yMovement);
}
if (direction == Direction.DOWN){
this.yMovement = Math.max(0,this.yMovement);
}
}
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