如何在Pygame模块中碰撞两个图像

如何解决如何在Pygame模块中碰撞两个图像

我是编程的新手，了解Python的基础知识，想问一下如果两个图像重叠一点，然后在pygame中按下特定的按钮，该如何执行动作。游戏如下：

import pygame
import random

pygame.init()
window = pygame.display.set_mode((1000,600))
caption = pygame.display.set_caption(
    'Test your reaction speed. Shoot the target game!')  # sets a caption for the window
game_running = True  # this is the gameloop so the window stays open

PlayerImg = pygame.image.load('F:\PythonPortable\oscn.png')
PlayerX = 370
PlayerY = 420
PlayerX_change = 0
PlayerY_change = 0


def player():
    window.blit(PlayerImg,(PlayerX,PlayerY))


aim_sight = pygame.image.load('F:\PythonPortable\ktarget.png')
aim_sightX = 460
aim_sightY = 300
aim_sight_changeX = 0
aim_sight_changeY = 0


def aim_sight_function(x,y):
    window.blit(aim_sight,(x,y))


targetedImg = pygame.image.load('F:\PythonPortable\ktargetedperson.png')
targetedX = random.randint(0,872)
targetedY = random.randint(0,200)


def random_target():
    window.blit(targetedImg,(targetedX,targetedY))


while game_running:
    window.fill((255,255,255))
    random_target()
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            game_running = False
        if event.type == pygame.KEYDOWN:
            if event.key == pygame.K_LEFT:
                aim_sight_changeX = -2
                PlayerX_change = -2
            elif event.key == pygame.K_RIGHT:
                aim_sight_changeX = 2
                PlayerX_change = 2
            elif event.key == pygame.K_UP:
                aim_sight_changeY = -2
                PlayerY_change = -2
            elif event.key == pygame.K_DOWN:
                aim_sight_changeY = 2
                PlayerY_change = 2
        elif event.type == pygame.KEYUP:
            if event.key == pygame.K_LEFT or event.key == pygame.K_RIGHT:
                aim_sight_changeX = 0
                PlayerX_change = 0
            elif event.key == pygame.K_UP or event.key == pygame.K_DOWN:
                aim_sight_changeY = 0
                PlayerY_change = 0

    aim_sightX += aim_sight_changeX
    if aim_sightX <= 46.5:
        aim_sight_changeX = 0
    elif aim_sightX >= 936:
        aim_sight_changeX = 0
    aim_sightY += aim_sight_changeY
    if aim_sightY <= 0:
        aim_sight_changeY = 0
    elif aim_sightY >= 400:
        aim_sight_changeY = 0

    PlayerX += PlayerX_change
    if PlayerX <= -50:
        PlayerX_change = 0
    elif PlayerX >= 850:
        PlayerX_change = 0
    player()
    aim_sight_function(aim_sightX,aim_sightY)
    pygame.display.update()

我想知道我该怎么做。我想也许是

if event.type == pygame.K_SPACE and targetedX == targetedX in range(aim_sightX - 100,aim_sightY + 100) or targetedY == targetedY in range (aim_sightY - 100,aim_sightY + 100):
...

我看过的所有教程似乎都没有涵盖该主题，并且希望获得涵盖该问题或直接答案的教程的建议。

解决方法

我建议使用pygame.Rect对象和colliderect()查找两个 Surface 对象之间的碰撞。 pygame.Surface.get_rect.get_rect()返回一个矩形，该矩形的大小为 Surface 对象，由于 Surface 对象没有位置，因此该矩形始终以（0，0）开始。矩形的位置可以通过关键字参数指定：

PlayerImg_rect   = PlayerImg.get_rect(topleft = (PlayerX,PlayerY))
targetedImg_rect = targetedImg .get_rect(topleft = (targetedX,targetedX))

if PlayerImg_rect.colliderect(targetedImg_rect):
    print("hit")