运行时错误3265:在此集合中找不到项目

如何解决运行时错误3265:在此集合中找不到项目

我一直收到“运行时错误'3265':在此集合中找不到项目”。错误消息。

它发生的行是:If rs!Borings.[Custom Sampling Method] = False Then,这是被引用字段的第一个实例,因此让我想知道SQL是否已正确添加到字符串中。但是我将字符串打印到“立即”窗口中,并显示:

SELECT Borings.ProjectID,Borings.BoringID,Borings.HoleDepth,Samples.BoringID,Samples.Number,Samples.Depth,Samples.Length,Borings.[Continuous To],Borings.[Every Other],Borings.[Sample Length],Borings.[Custom Sampling Method] 
FROM Borings LEFT JOIN Samples ON Borings.BoringID = Samples.BoringID 
   WHERE Borings.ProjectID = 462

对我来说看起来是正确的..错了吗?我想知道最后的值是否应该用引号引起来?

如果我改用Set rs = db.OpenRecordset("qryAddSamples"),则该方法不起作用。我最终遇到另一个运行时错误'3061',参数太少。应该是1.我不知道那是什么意思。

要了解代码的用途,应根据钻孔表中的采样信息为当前装载的每个项目的每个土壤钻孔生成土壤样本。

Option Compare Database

Dim db As DAO.Database
Dim rs As DAO.Recordset


Private Sub Update_Samples_Click()

    DoCmd.RunCommand acCmdSaveRecord

    Dim strSQL As String
    Dim sampleDepth As Integer
    Dim sampleNumber As Integer
    
    strSQL = "SELECT Borings.ProjectID," & _
             "Samples.Number," & _
             "Borings.[Every Other],Borings.[Custom Sampling Method] " & _
             "FROM Borings LEFT JOIN Samples ON Borings.BoringID = Samples.BoringID " & _
             "WHERE Borings.ProjectID = " & [TempVars]![tmpProjectID]
        
    Debug.Print strSQL
        
    Set db = CurrentDb
    Set rs = db.OpenRecordset(strSQL)

    sampleDepth = 0
    sampleNumber = 1
    
    Do While Not rs.EOF
        
        If rs!Borings.[Custom Sampling Method] = False Then

        Do While sampleDepth + rs!Borings.[Sample Length] <= rs!Borings.[Continuous To]

        rs.AddNew
        AddSamples
        
        sampleNumber = sampleNumber + 1
        sampleDepth = sampleDepth + rs!Samples.[Length]
       
        Loop
        
        Do While sampleDepth + rs!Borings.[Sample Length] <= rs!Borings.HoleDepth
        
        rs.AddNew
        AddSamples
        
        sampleNumber = sampleNumber + 1
        sampleDepth = sampleDepth + rs!Borings.[Every Other]

        Loop
        
        End If

        rs.MoveNext

    Loop
    
    rs.Close
    
    Set rs = Nothing
    Set db = Nothing
    
    DoCmd.Close
    DoCmd.OpenForm "Main"

End Sub

Private Sub AddSamples()
        rs!Samples.[BoringID] = rs!Borings.BoringID
        rs!Samples.[Sample Number] = sampleNumber
        rs!Samples.[Depth] = sampleDepth
        rs!Samples.[Length] = rs!Borings.[Sample Length]
        rs.Update
End Sub

解决方法

尝试使用属性 Value 来更具体,因为rs!SomeField字段对象。 另外,在不需要的地方省略表名:

    Do While Not rs.EOF
        
        If rs![Custom Sampling Method].Value = False Then

            Do While sampleDepth + rs![Sample Length].Value <= rs![Continuous To].Value

                rs.AddNew
                AddSamples
                
                sampleNumber = sampleNumber + 1
                sampleDepth = sampleDepth + rs!Length.Value
        
            Loop
            
            Do While sampleDepth + rs![Sample Length].Value <= rs!HoleDepth.Value
            
                rs.AddNew
                AddSamples
                
                sampleNumber = sampleNumber + 1
                sampleDepth = sampleDepth + rs![Every Other].Value

            Loop
        
        End If

        rs.MoveNext

    Loop
,

在将bBoringID的值分配给记录集中的sBoringID字段时遇到麻烦。在向Samples表中添加新样本时,需要从Borings表中获取当前bBoringID并将其分配给Samples表中的sBoringID。每当到达rs!sBoringID.Value = rs!bBoringID.Value行时,我都会收到“运行时错误3162:您试图将Null值分配给不是Variant数据类型的变量”错误。

但是,将值正确打印到立即窗口中,除了在值的前面和结尾有一个空格。但是当我将鼠标悬停在变量上并且监视变量时,标题都显示为Null。

Dim db As DAO.Database
Dim rs As DAO.Recordset


Private Sub Update_Samples_Click()

    DoCmd.RunCommand acCmdSaveRecord
    
    Dim strSQL As String
    Dim sampleDepth As Long
    Dim sampleNumber As Long

    strSQL = "SELECT Borings.ProjectID,Borings.BoringID as bBoringID,Borings.HoleDepth," & _
             "Samples.BoringID as sBoringID,Samples.Number,Samples.Depth,Samples.Length," & _
             "Borings.[Continuous To],Borings.[Every Other],Borings.[Sample Length]," & _
             "Borings.[Custom Sampling Method] " & _
             "FROM Borings LEFT JOIN Samples ON Borings.BoringID = Samples.BoringID " & _
             "WHERE Borings.ProjectID = " & [TempVars]![tmpProjectID]
    
    Set db = CurrentDb
    Set rs = db.OpenRecordset(strSQL)
    rs.MoveFirst
    
    Debug.Print strSQL
    Debug.Print rs!ProjectID.Value                  'Borings Table
    Debug.Print rs!bBoringID.Value                  'Borings Table
    Debug.Print rs!HoleDepth.Value                  'Borings Table
    Debug.Print rs![Continuous To].Value            'Borings Table
    Debug.Print rs![Every Other].Value              'Borings Table
    Debug.Print rs![Sample Length].Value            'Borings Table
    Debug.Print rs![Custom Sampling Method].Value   'Borings Table
    Debug.Print rs!sBoringID.Value                  'Samples Table
    Debug.Print rs!Number.Value                     'Samples Table
    Debug.Print rs!Depth.Value                      'Samples Table
    Debug.Print rs!Length.Value                     'Samples Table
    Debug.Print [TempVars]![tmpProjectID]

    sampleDepth = 0
    sampleNumber = 1
    
    Do While Not rs.EOF
        
        If rs![Custom Sampling Method].Value = False Then

        Do While sampleDepth + rs![Sample Length].Value <= rs![Continuous To].Value

                  rs.AddNew
>>this line >>    rs!sBoringID.Value = rs!bBoringID.Value
                  rs![Sample Number].Value = sampleNumber
                  rs!Depth.Value = sampleDepth
                  rs!Length.Value = rs![Sample Length].Value
                  rs.Update
Immediate window output:
SELECT Borings.ProjectID,Samples.BoringID as sBoringID,Borings.[Continuous To],Borings.[Custom Sampling Method] FROM Borings LEFT JOIN Samples ON Borings.BoringID = Samples.BoringID WHERE Borings.ProjectID = 462
 462    'Why is there a space before and after all these integer values?
 848    'Why is there a space before and after all these integer values? 
 60     'Why is there a space before and after all these integer values?
 10     'Why is there a space before and after all these integer values?
 5      'Why is there a space before and after all these integer values?
 2      'Why is there a space before and after all these integer values?
False
Null
Null
Null
Null
462
,

没关系,经过更多研究后,我修复了它。由于bBoringID是Borings表中的一个自动编号,因此不需要将其输入到Samples表中。 Access将在“样品”表中自动输入相同的键值。我删除了rs!sBoringID.Value = rs!bBoringID.Value,终于看到了其他rs!字段中的所有值。

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