HTML模板中的Django分页

如何解决HTML模板中的Django分页

我想使用分页，但是我无法使用html。

views.py

def blog_list(request):
    articles = Blogmodel.objects.all()
    page = request.GET.get('page',1)
    paginator = Paginator(articles,20)
    

    try:
        page = paginator.page(page)
    except PageNotAnInteger:
        page = paginator.page(1)
    except EmptyPage:
        page = paginator.page(paginator.num_pages)
    args = {'articles':articles,'page':page}
    return render(request,'blog.html',args)

html

<nav aria-label="Page navigation example">
  <ul class="pagination">
    <li class="page-item"><a class="page-link" href="#">PrevIoUs</a></li>
    <li class="page-item"><a class="page-link" href="#">1</a></li>
    <li class="page-item"><a class="page-link" href="#">2</a></li>
    <li class="page-item"><a class="page-link" href="#">3</a></li>
    <li class="page-item"><a class="page-link" href="#">Next</a></li>
  </ul>
</nav>

谁能帮助我，如何在html中做到这一点？

解决方法

这是Corey MS的摘录。

{% if is_paginated %}
    {% if page_obj.has_previous %}
        <a href="?page=1">First</a>
        <a href="?page={{ page_obj.previous_page_number}}">Previous</a>
    {% endif %}

    {% for num in page_obj.paginator.page_range %}
        {% if page_obj.number == num %}
            <a href="?page={{ num }}">{{ num }}</a>
        {% elif num > page_obj.number|add:'-3' %}
            <a href="?page={{ num }}">{{ num }}</a>
        {% elif num > page_obj.number|add:'3' %}
            <a href="?page={{ num }}">{{ num }}</a>
        {% endif %}
    {% endfor %}

    {% if page_obj.has_next %}
        <a href="?page={{ page_obj.next_page_number }}">Next</a>
        <a href="?page={{ page_obj.paginator.num_pages}}">Last</a>
    {% endif %}
{% endif %}