如何解决Django&Geopy:每个帖子列出的所有距离:如何将一个距离与一个帖子关联
Django-Geopy
我正在寻找如何定义两点之间的距离。第一个与帖子本身相关,并且不会针对每个帖子进行更改。它指示职位的位置。第二个将链接到用户的位置。
问题:假设我已建立联系:每个帖子都列出了所有距离
我得到一个帖子: [459.414,459.414,459.414,0.605,0.605,0.605,0.605,0.605,459.414,0.605] km
user/models.py
class UserProfile(models.Model):
...
latitude = models.DecimalField(max_digits=9,decimal_places=6,blank=True,default='0')
longitude = models.DecimalField(max_digits=9,default='0')
post/models.py
class Cuisine(models.Model):
...
latitude_user = models.DecimalField(max_digits=9,default='0')
longitude_user = models.DecimalField(max_digits=9,default='0')
感谢@tgrandje,我已经解决了一些问题,可以从UserProfile
中找到价值:
问题是我总是为每个帖子获得相同的距离。
有什么建议吗?
def Homemainpage(request):
post = Cuisine.objects.filter(status=0).order_by('-publishing_date').all() #All cuisine
if request.user.is_authenticated:
if request.user.userprofile.full_address:
distance = []
for p in post:
post_lon = p.longitude_user
post_lat = p.latitude_user
post_situation = (post_lon,post_lat)
user_lon = UserProfile.objects.filter(user=request.user)[0].longitude
user_lat = UserProfile.objects.filter(user=request.user)[0].latitude
user_situation = (user_lon,user_lat)
distance.append(round(geodesic(post_situation,user_situation).km,3))
# Pre commande pour demain
#post = Cuisine.objects.filter(status=0).filter(start_date=Now().date() + timedelta(days=1)).order_by('-publishing_date').all()
# En commande pour aujourd'hui
#post = Cuisine.objects.filter(status=0).filter(start_date=Now().date()).order_by('-publishing_date').all()
paginator = Paginator(post,3)
page_number = request.GET.get('page')
page_obj = paginator.get_page(page_number)
listaliments = ListAliments.objects.filter(status=1).all()
typerepas = Typerepas.objects.filter(status=1).all()
sperepas = Sperepas.objects.filter(status=1).all()
return render(request,'index.html',{
'post': post,'listaliments': listaliments,'typerepas': typerepas,'sperepas': sperepas,'page_obj': page_obj,'today' : Now().date(),'tomorrow': Now().date() + timedelta(days=1),'distance': distance,})
解决方法
如果您已准备好所有纬度/经度,则可以使用pyproj,它非常有效:
from pyproj import Geod
...
user_lon = UserProfile.objects.filter(user=self.request.user).get(self.longitude)
user_lat = UserProfile.objects.filter(user=self.request.user).get(self.latitude)
post_lon = Cuisine.objects.filter(slug=slug).get(self.longitude_user)
post_lat = Cuisine.objects.filter(slug=slug).get(self.latitude_user)
wgs84_geod = Geod(ellps='WGS84')
*_args,dist_meters = wgs84_geod.inv(user_lon,user_lat,post_lon,post_lat)
print(dist_meters)
编辑
def Homemainpage(request):
post = Cuisine.objects.filter(status=0).order_by('-publishing_date').all() #All cuisine
...
user_lon = UserProfile.objects.filter(user=request.user)[0].longitude
user_lat = UserProfile.objects.filter(user=request.user)[0].latitude
wgs84_geod = Geod(ellps='WGS84')
kitchen_distance_dict = dict()
for kitchen in Cuisine.objects.all():
post_lon = kitchen.longitude
post_lat = kitchen.latitude
*_args,post_lat)
kitchen_distance_dict[kitchen.pk] = dist_meters / 1000
return render(request,'index.html',{
'post': post,'listaliments': listaliments,'typerepas': typerepas,'sperepas': sperepas,'page_obj': page_obj,'distance': kitchen_distance_dict,})
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