如何解决如何使用react-testing-library检查Material-ui MenuItem是否被禁用
我正在使用Material-UI和react来构建Dropdown
组件。
Dropdown.tsx
import React from "react";
import ClickAwayListener from "@material-ui/core/ClickAwayListener";
import Grow,{ GrowProps } from "@material-ui/core/Grow";
import Input from "@material-ui/core/Input";
import MenuList from "@material-ui/core/MenuList";
import Paper from "@material-ui/core/Paper";
import Popper from "@material-ui/core/Popper";
import MenuItem from "@material-ui/core/MenuItem";
export default function Dropdown(props: {
onSearch: (suggestion: string) => void;
}) {
const [searchText,setSearchText] = React.useState("");
const [open,setopen] = React.useState(false);
let searchElement: null | HTMLElement = null;
const onSearchTextChange = (event: React.ChangeEvent<HTMLInputElement>) => {
setSearchText(event.target.value);
setopen(true);
};
const openSearchSuggestion = () => {
setopen(true);
};
const setSearchElement = (node: null | HTMLElement) => {
searchElement = node;
};
const closeSearchSuggestion = () => {
setopen(false);
};
const handleOnClickAway = (event: React.MouseEvent<EventTarget>) => {
if (searchElement && searchElement.contains(event.target as HTMLElement)) {
return;
}
closeSearchSuggestion();
};
const handleSearchSuggestionClick = (suggestion: string) => (
event: React.MouseEvent<EventTarget>
) => {
props.onSearch(suggestion);
};
const searchSuggestionsRenderer = (suggestion: string,index: number) => {
return (
<MenuItem
key={index}
onClick={handleSearchSuggestionClick(suggestion)}
className="suggestion-item"
id={`suggestion-item-${index}`}
disabled={suggestion === "Criteria 2"}
>
{searchText} in {suggestion}
</MenuItem>
);
};
const popperTrans = ({ TransitionProps }: { TransitionProps: GrowProps }) => {
const searchSuggestions = ["Criteria 1","Criteria 2"];
return (
<Grow {...TransitionProps} style={{ transformOrigin: "0 0 0" }}>
<Paper className="search-suggestions-paper">
<ClickAwayListener onClickAway={handleOnClickAway}>
<MenuList>
{searchText &&
searchSuggestions &&
searchSuggestions.map(searchSuggestionsRenderer)}
</MenuList>
</ClickAwayListener>
</Paper>
</Grow>
);
};
return (
<div>
<Input
inputRef={setSearchElement}
className="search-input"
placeholder="Search"
value={searchText}
onChange={onSearchTextChange}
onFocus={openSearchSuggestion}
data-testid="searchInput"
/>
<Popper
className="search-suggestion-popper"
open={open && searchText.trim().length >= 2}
anchorEl={searchElement}
placement="bottom-start"
transition={true}
>
{popperTrans}
</Popper>
</div>
);
}
我现在正在使用react-testing-library测试该组件。我想检查下拉菜单中的第二个选项是否被禁用。我尝试检查单击第二个选项时是否未调用在菜单项单击时调用的onSearch函数。
测试检查选项已禁用
test('that criteria 2 option is disabled',() => {
const props = { onSearch: jest.fn() }
const { getAllByRole,getByTestId } = render(<Dropdown {...props} />);
const Input = getByTestId('searchInput');
const TextBox = globalGetByRole(Input,'textBox') as HTMLInputElement;
fireEvent.change(TextBox,{ target: { value: 'test' } });
const MenuItems = getAllByRole('menuitem');
expect(MenuItems.length).toBe(2);
const Criteria2MenuItem = MenuItems[1];
fireEvent.click(Criteria2MenuItem);
expect(props.onSearch).toHaveBeenCalledTimes(0);
});
但是这没有用。该函数被调用一次。为什么会发生这种情况,我该如何测试要测试的内容?
解决方法
例如,当您禁用Material-UI MenuItem
<MenuItem disabled>
{...}
</MenuItem>
它将aria-disabled="true"
和Mui-disabled
CSS类添加到DOM中的li
元素中。 li
不是有效的按钮,因此您无法通过单击对其进行测试。您需要使用aria-disabled
中的.toHaveAttribute()
检查它是否具有jest-dom
属性。
expect(Criteria2MenuItem).toHaveAttribute("aria-disabled")
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