如何解决是否有可能在dict中获得dict的选择性组合?
在字典中使用组合键运行时,我遇到了一些困难,下面我将解释所有这些情况。
name_list = {
1 : {'_name' :'michael','id' : '001','rating': '10','role' :'general_manager'},2 : {'_name' :'mohamad','id' : '002','rating': '9.5','role' :'team_leader'},3 : {'_name' :'johnny','id' : '003','rating': '9','role' :'developer'},4 : {'_name' :'nicholos','id' : '004','role' :'tech_support'},5 : {'_name' :'nawaz','id' : '005','rating': '8.5','role' :'intern'}
}
new_list = {}
num =0
fab_four = combinations(name_list,4)
for i in range(len(fab_four)):
j = new_list[i]
for key,value in j.items():
num= num+1
new_list[num] = name_list[i]
我的预期输出:
new_list = {
{
1 : {'_name' :'michael','role' :'tech_support'}
},{
1 : {'_name' :'michael','role' :'intern'}
}
}
像预期的输出一样,我需要在新字典中使用所有组合吗?
解决方法
您可以使用以下命令获得前面提到的输出:
new_list={}
fab_four = list(combinations(name_list,4))
for j in range(len(fab_four)):
new_list[j+1] = {i:name_list[i] for i in fab_four[j]}
输出:
{1:{1: {'_name': 'michael','id': '001','rating': '10','role': 'general_manager'},2: {'_name': 'mohamad','id': '002','rating': '9.5','role': 'team_leader'},3: {'_name': 'johnny','id': '003','rating': '9','role': 'developer'},4: {'_name': 'nicholos','id': '004','role': 'tech_support'}},2: {1: {'_name': 'michael',5: {'_name': 'nawaz','id': '005','rating': '8.5','role': 'intern'}},3: {1: {'_name': 'michael','role': 'tech_support'},4: {1: {'_name': 'michael',5: {2: {'_name': 'mohamad','role': 'intern'}}}
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