mongodb查询以将子文档显示为主文档并对其进行分页

如何解决mongodb查询以将子文档显示为主文档并对其进行分页

首先,我有这种类型的模型:

const produkSchema = new mongoose.Schema({
    nama_produk: String,etalase: {type: mongoose.Schema.Types.ObjectID,ref: 'kategori'},kategori: {type: mongoose.Schema.Types.ObjectID,jenis: {type: mongoose.Schema.Types.ObjectID,ref: 'kategori.jenis'},bahan: String,warna: String,deskripsi: String,foto_produk: [String],harga: Number,link_bukalapak: String,link_shopee: String,link_tokopedia: String,link_lazada: String,link_website: String,display: {type: Boolean,default: false},},{
    weights: {
        nama_produk: 5,timestamps: true
})

const tokoSchema = new mongoose.Schema({
    username: {type: String,trim: true},password: {type: String,required: true,select: false},merek: String,listMerek: [{type: mongoose.Schema.Types.ObjectID,ref: 'produk'}],follower: [{type: mongoose.Schema.Types.ObjectID,ref: 'user'}],email: {type: String,trim: true,unique: true},instagram: String,whatsapp: String,website: String,alamat: String,foto_profil: String,bukalapak: String,shopee: String,tokopedia: String,fotoktp: String,banner: [{
        gambar: {type: String,// order: {type: Number,required: true},}],produk: [produkSchema],etalase: [{type: mongoose.Schema.Types.ObjectID,ref: 'kategori'}],// etalase: [{
    //     kategori: {type: mongoose.Schema.Types.ObjectID,//     order: {Number}
    // }],approve: {type: Number,default: 0},// 0: pending,1: reject,2: approve
    populer: {type: Boolean,gambar_populer: [String],pilihan: {type: Boolean,{timestamps: true});

,我有一个端点可以用以下代码过滤produkSchema

exports.filterProduk = (req,res) => {
    const {merek,warna,kategori,jenis,hargaAwal,hargaAkhir,skip,limit} = req.body

    let query = {}
    const $and = []

    if (merek) {
        $and.push({$or: merek.map(id => ({_id: mongoose.Types.ObjectId(id)}))})
    }

    if (warna) {
        $and.push({$or: warna.map(warna => ({"produk.warna": warna}))})
    }

    if (kategori) {
        query["produk.etalase"] = mongoose.Types.ObjectId(kategori)
    }

    if (jenis) {
        $and.push({$or: jenis.map(id => ({"produk.jenis": mongoose.Types.ObjectId(id)}))})
    }

    if (hargaAwal !== '') {
        query["produk.harga"] = {
            $gte: parseInt(hargaAwal),}
    }
    if (hargaAkhir !== '') {
        query["produk.harga"] = {
            $lte: parseInt(hargaAkhir)
        }
    }

    if ($and.length > 0) {
        query = {$and,...query}
    }

    toko.aggregate([
        {$unwind: '$produk'},{$match: query},{
            $lookup: {
                from: "kategoris",as: "produk.etalase",let: {pjid: "$produk.jenis"},pipeline: [
                    {$unwind: "$jenis"},{$match: {$expr: {$eq: ["$$pjid","$jenis._id"]}}},{
                        $project: {
                            "jenis._id": 1,"jenis.label": 1
                        }
                    }
                ]
            }
        },{$unwind: {path: "$produk.etalase"}},{$group: {_id: '$_id',produk: {$push: '$produk'},foto_profil: {$first: '$foto_profil'}}},{$limit: skip + limit},{$skip: skip}
    ])
        .then(async data => {
            res.status(200).json({data,prefix: {produk: "uploads/produk",toko: "uploads/toko"}})
        })
}

实际结果是:

[
{_id: blabla,foto_profil: "blabla",produk:[{nama_produk: "blabla",bahan: "blabla",...rest ProdukSchema as query}]
},{_id: blabla,...rest ProdukSchema as query}]
}
]

预期:

[
{nama_produk: "blabla",...rest ProdukSchema as query,foto_profil(from toko schema): "blabla"},{nama_produk: "blabla",foto_profil(from toko schema): "blabla"}
]

并对此produkSchema进行分页(限制和偏移)

实际上,在此之前,我已经在here进行了此查询,但是该查询将产生大量数据,需要分页,

我该怎么做?我应该将produkSchema拆分为主要子文档吗?或对此条件存在任何查询吗?

解决方法

我不确定确切的要求,但我可以猜测2个选择,

  • 假设变量:
let skip = 0;
let limit = 10;

第一个选项:

  • 从末尾删除$group个阶段,并在$unwind个阶段之后开始
  • $replaceRoot使用produk合并对象foto_profil$mergeObjects并替换根
  {
    $replaceRoot: {
      newRoot: {
        $mergeObjects: [{ foto_profil: "$foto_profil" },"$produk"]
      }
    }
  },{ $skip: skip * limit },{ $limit: limit }

Playground


第二个选项:

  • 从末尾删除$group个阶段,并在$unwind个阶段之后开始
  • $group(按Toko ID和Produk ID),这将对produk进行分组并获得唯一的第一个produk
  • $replaceRoot使用produk合并对象foto_profil$mergeObjects并替换根
  {
    $group: {
      _id: {
        _id: "$_id",produk_id: "$produk._id"
      },root: { $first: "$$ROOT" }
    }
  },{
    $replaceRoot: {
      newRoot: {
        $mergeObjects: [{ foto_profil: "$root.foto_profil" },"$root.produk"]
      }
    }
  },{ $limit: limit }

Playground

,

也许您可以在查找后执行此操作:

  1. $ unwind produk(其中produk仍为数组类型,然后将其展开)。
  2. $ group:{_id:nama_produk等...}
  3. $ project ......或您想做的任何事情。

因此您可以通过nama_produk作为_id获取组列表。

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