MediaChange的Angular Flex-Layout MediaObserver优先级

如何解决MediaChange的Angular Flex-Layout MediaObserver优先级

通过MediaObserver观察媒体更改时,如何获取MediaChange []的当前更改?

我观察到当前是数组MediaChange []中的第一项,我可以使用第一项。我还观察到,在MediaChange中具有优先级,我也观察到当前的更改具有最高优先级。哪一个最好?

工作代码示例:

  constructor(mediaObserver: MediaObserver) {
    this.mediaObserverAsObservable = mediaObserver.asObservable().subscribe((changes: MediaChange[]) => {
      // option A.
      const currentMediaChange = changes[0];
      if (currentMediaChange.mqAlias === 'sm' || currentMediaChange.mqAlias === 'xs') {
        if (this.sidenav) {
          this.sidenav.close();
        }
      } else {
        if (this.sidenav) {
          this.sidenav.open();
        }
      }
      
      // Option B.
      const maxPriority = changes.reduce(
        (currentMax,mediaChange) => (mediaChange.priority > currentMax ? mediaChange.priority : currentMax),changes[0].priority
      );
      const currentMediaChange = changes.find(mc => mc.priority === maxPriority);
      if (currentMediaChange) {
        if (currentMediaChange.mqAlias === 'sm' || currentMediaChange.mqAlias === 'xs') {
          if (this.sidenav) {
            this.sidenav.close();
          }
        } else {
          if (this.sidenav) {
            this.sidenav.open();
          }
        }
      }
    });
  }

或者我可以使用mediaObserver.isActive()来识别与当前视口匹配的查询?

谢谢。

解决方法

7.0.0-beta.24 (2019-03-17)import SwiftUI class SampleOO: ObservableObject { @Published var name: String = "init name" } //ParentView struct OOSample: View { //The first version of an @EnvironmentObject is an @ObservedObject or @StateObject //https://developer.apple.com/tutorials/swiftui/handling-user-input @ObservedObject var sampleOO: SampleOO = SampleOO() var body: some View { VStack{ Button("change-name",action: { self.sampleOO.name = "OOSample" }) Text("OOSample = " + sampleOO.name) //Doing this should fix your error code with no other workarounds ChildEO().environmentObject(sampleOO) SimpleChild(name: sampleOO.name) } } } //Can Display and Change name struct ChildEO: View { @EnvironmentObject var sampleOO: SampleOO var body: some View { VStack{ //Can change name Button("ChildEO change-name",action: { self.sampleOO.name = "ChildEO" }) Text("ChildEO = " + sampleOO.name) } } } //Can only display name struct SimpleChild: View { var name: String var body: some View { VStack{ //Cannot change name Button("SimpleChild - change-name",action: { print("Can't change name") //self.name = "SimpleChild" }) Text("SimpleChild = " + name) } } } struct OOSample_Previews: PreviewProvider { static var previews: some View { OOSample() } } 进行了中断更改,因此可以观察到angular/flex-layout返回mediaObserver.asObservable()

MediaChange source code具有一个称为优先级的属性,该属性为您提供激活的优先级,在MediaChange[]上的外观按descendent order排序。

换句话说,最高优先级是第一位。选项A我认为,这是基于上面的最佳选择。因为您应该选择活动的MediaChange[],所以它是最高优先级。当我们知道它排在第一位时,就不需要使用mediaQuery

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