如何解决有条件的Groupyby计数
我正在努力解决下面所附代码的最后一行。在最后一行中,我试图获取所有等于或小于10的“ PM_Temp”的计数,但是我不知道该怎么写。任何帮助将不胜感激
df1 = df.groupby(['City','year'])\
.agg(Avg_Duration = ('duration','mean'),Max_Duration = ('duration','max'),Min_Duration = ('duration','min'),Ave_AM_Temp = ('AM_Temp',Max_AM_Temp = ('AM_Temp',Min_AM_Temp = ('AM_Temp',Ave_PM_Temp = ('PM_Temp',Max_PM_Temp = ('PM_Temp',Min_PM_Temp = ('PM_Temp',PM_Temp_10_or_less = (('PM_Temp',(<=10).count())
解决方法
在此处使用lambda函数:
df1 = df.groupby(['City','year'])\
.agg(Avg_Duration = ('duration','mean'),Max_Duration = ('duration','max'),Min_Duration = ('duration','min'),Ave_AM_Temp = ('AM_Temp',Max_AM_Temp = ('AM_Temp',Min_AM_Temp = ('AM_Temp',Ave_PM_Temp = ('PM_Temp',Max_PM_Temp = ('PM_Temp',Min_PM_Temp = ('PM_Temp',PM_Temp_10_or_less = ('PM_Temp',lambda x: x.le(10).sum())
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