检查userinput是否匹配随机整数的任何数字

如何解决检查userinput是否匹配随机整数的任何数字

random = random.randint(1000,9999)
guess = int(input("Enter your guess: "))
while guess != random:
    guess = int(input("That was incorrect! Enter your guess: "))

这是一个非常简单的猜谜游戏，但是我想提供一些东西，在每一次不成功的尝试之后，它都会说出四位数中有多少数字是正确的。

我没有尝试过，主要是因为我不确定该怎么做。

例如

random = 1234
Enter your guess: 1111
You guessed 1 number correct
Enter your guess: 1222
You guessed 2 numbers correct
...... and so on

解决方法

如果您的意思是职位

random = random.randint(1000,9999)
guess = int(input("Enter your guess: "))
while guess != random:
    right = 0
    index = 0
    for char in str(guess):
        if char == str(random)[index]:
            index += 1
            right += 1
    print(f'{right} were right')
    guess = int(input("That was incorrect! Enter your guess: "))

,

如果您确实希望将两个数字都保持为int，则可以使用％（取模运算符）来查找整数除以10的基数后的余数。

例如。

    correctnum = 0
    random = 1234
    guess = 1111
    if ((((random-(random % 1000 )) /1000) == (((guess-(guess % 1000 )) /1000)):
      correctnum++

对于100/10/1重复的公式应都比较该“点”中的数字，而不必转换数据类型。在此之后输出正确数字的值，您应该拥有所需的内容。

,

random = 1234
random = str(random)

#guess = str(input('enter your guess'))
guess = '1222'
correct = 0
for i in range(len(guess)):
    if guess[i] == random[i]:
        correct += 1

print(correct)
ouput: 2

或简单地：

correct = sum(guess[i] == random[i] for i in range(len(guess)))