使用Python从电子邮件正文中删除某些文本

如何解决使用Python从电子邮件正文中删除某些文本

我正在尝试使用以下Python代码解析转发的电子邮件正文

import imapclient
import os
import pprint
import pyzmail
import email

#my email info
EMAIL_ADRESS = os.environ.get('DB_USER')
EMAIL_PASSWORD = os.environ.get('PYTHON_PASS')

#login to my email
imap0bj =  imapclient.IMAPClient('imap.gmail.com',ssl = True)
imap0bj.login(EMAIL_ADRESS,EMAIL_PASSWORD )
print("ok")


pprint.pprint(imap0bj.list_folders())
#Selecting my InBox
imap0bj.select_folder('INBox',readonly = True)

#Getting UIDs from InBox
UIDs = imap0bj.search(['SUBJECT','Contact FB Applicant','ON','16-Oct-2020'])
print(UIDs)


rawMessages = imap0bj.fetch(UIDs,['BODY[]'])
message = pyzmail.PyzMessage.factory(rawMessages[9999][b'BODY[]'])

message.text_part != None
#Body of the email returned as a string
msg = message.text_part.get_payload().decode(message.text_part.charset)

print(msg)

imap0bj.logout()

此代码输出与此类似的字符串

   ---------- Forwarded message ---------
    From: Someone <Mail@mail.biz>
    Date: Wed,Oct 14,2020 at 1:23 PM
    Subject: Fwd: ? Contact FB Applicant?
    To: <mail@mail.com>
    
    
    
    
   ---------- Forwarded message ---------
    From: Someone <Mail@mail.biz>
    Date: Wed,2020 at 1:23 PM
    Subject: Fwd: ? Contact FB Applicant?
    To: <mail@mail.com>
    
    
    The following applicant filled out the form via Facebook.  Contact
    immediately.
    
    Some Guy
    999999999999
    mail@mail.com

但是我不希望“转发邮件”部分。我只想从“以下申请人...”开始，然后才是我关心的信息。我如何摆脱其他东西？我非常感谢您的帮助。谢谢！

解决方法

您可以使用io.StringIO

这是您的用法。

from io import StringIO

# your code goes here
...
...

msg = message.text_part.get_payload().decode(message.text_part.charset)

sio = StringIO(msg)

sio.seek(msg.index('The following applicant'))

for line in sio:
  print(line)

工作原理：

StringIO允许您将字符串视为流（文件）。 StringIO.seek将流的位置移动到特定位置。（0是流的开头） str.index返回字符串在字符串中的第一位置。放在一起：将流的开头移至所需字符串的第一个出现位置，然后从流中读取。

从这种格式来看，您需要逐行阅读。如果遇到以'---'开头的行，例如line [：3] ='---' 您忽略它及其后的行，直到您读到空行，如果再次以“-”开头，请重复此过程然后，第一个非空行应为“以下申请人...”

您可以将此代码埋入无限循环并中断，这是伪代码

while True:
  line = read next line
  if length(line) ==0: continue
  if line[:3] = '---'
    while true:
      line = read next line
      if line:
        break
      else:
        continue
  else:
    break
read lines and print everthing from here

假设读取行函数记录了已读取的行数以及将要读取的行。