如何解决如何在Linq C#中使用分区?
Currency Exchange Date
USD NewYork 01/12/20
USD NewYork 01/11/20
USD NewYork 01/10/20
USD Montreal 01/10/20
CAD Montreal 01/07/20
CAD Montreal 01/06/20
CAD Beijing 01/06/20
我正在使用使用分区的查询
select distinct currency,first_value(exchange) over (partition by currency order by count(*) desc) exchange,max(count(*)) over (partition by currency) frequency
from tablename
group by currency,exchange
结果
Currency Exchange Frequency
USD NewYork 3
CAD Montreal 2
我需要在Linq中实现它
解决方法
尝试以下操作:
DataTable dt = new DataTable();
dt.Columns.Add("Currency",typeof(string));
dt.Columns.Add("Exchange",typeof(string));
dt.Columns.Add("Date",typeof(DateTime));
dt.Rows.Add(new object[] {"USD","NewYork",DateTime.Parse("01/12/20")});
dt.Rows.Add(new object[] {"USD",DateTime.Parse("01/11/20")});
dt.Rows.Add(new object[] {"USD",DateTime.Parse("01/10/20")});
dt.Rows.Add(new object[] {"USD","Montreal",DateTime.Parse("01/10/20")});
dt.Rows.Add(new object[] {"CAD",DateTime.Parse("01/07/20")});
dt.Rows.Add(new object[] {"CAD",DateTime.Parse("01/06/20")});
dt.Rows.Add(new object[] { "CAD","Beijing",DateTime.Parse("01/06/20") });
var results = dt.AsEnumerable()
.GroupBy(x => x.Field<string>("Currency"))
.Select(x =>
x.GroupBy(y => y.Field<string>("Exchange"))
.Select(z =>
new
{
Currency = x.Key,Exchange = z.Key,Frequency = z.Count()
})
.OrderByDescending(z => z.Frequency)
.First()
).ToList();
,
运行此查询(来自jdweng的答案)
Exchanges.GroupBy(x => x.Field<string>("Currency"))
.Select(x =>
x.GroupBy(y => y.Field<string>("Exchange"))
.Select(z =>
new
{
Currency = x.Key,Frequency = z.Count()
})
.OrderByDescending(z => z.Frequency)
.First()
).ToList()
在LINQPad中的结果
+----------+----------+-----------+
| Currency | Exchange | Frequency |
+----------+----------+-----------+
| USD | New York | 3 |
| CAD | Montreal | 2 |
+----------+----------+-----------+
这会生成SQL
SELECT [t4].[test],[t1].[Currency],[t4].[Exchange],[t4].[value] AS [Frequency]
FROM (
SELECT [t0].[Currency]
FROM [Exchanges] AS [t0]
GROUP BY [t0].[Currency]
) AS [t1]
OUTER APPLY (
SELECT TOP (1) 1 AS [test],[t3].[Exchange],[t3].[value]
FROM (
SELECT COUNT(*) AS [value],[t2].[Exchange]
FROM [Exchanges] AS [t2]
WHERE (([t1].[Currency] IS NULL) AND ([t2].[Currency] IS NULL)) OR (([t1].[Currency] IS NOT NULL) AND ([t2].[Currency] IS NOT NULL) AND ([t1].[Currency] = [t2].[Currency]))
GROUP BY [t2].[Exchange]
) AS [t3]
ORDER BY [t3].[value] DESC
) AS [t4]
ORDER BY [t4].[value] DESC
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