Swift-从C ++ - 编程之家

如何解决Swift-从C ++

作为我正在从蓝牙设备提取数据的项目的一部分，制造商为我提供了CRC8函数供使用。我正在用Swift编写应用程序，但是它们提供的功能是在C ++中。

以下是他们在C ++中提供的功能

unsigned char xTable_CRC8[]={0x00,0x07,0x0E,0x09,0x1C,0x1B,0x12,0x15,0x38,0x3F,0x36,0x31,0x24,0x23,0x2A,0x2D,0x70,0x77,0x7E,0x79,0x6C,0x6B,0x62,0x65,0x48,0x4F,0x46,0x41,0x54,0x53,0x5A,0x5D,0xE0,0xE7,0xEE,0xE9,0xFC,0xFB,0xF2,0xF5,0xD8,0xDF,0xD6,0xD1,0xC4,0xC3,0xCA,0xCD,0x90,0x97,0x9E,0x99,0x8C,0x8B,0x82,0x85,0xA8,0xAF,0xA6,0xA1,0xB4,0xB3,0xBA,0xBD,0xC7,0xC0,0xC9,0xCE,0xDB,0xDC,0xD5,0xD2,0xFF,0xF8,0xF1,0xF6,0xE3,0xE4,0xED,0xEA,0xB7,0xB0,0xB9,0xBE,0xAB,0xAC,0xA5,0xA2,0x8F,0x88,0x81,0x86,0x93,0x94,0x9D,0x9A,0x27,0x20,0x29,0x2E,0x3B,0x3C,0x35,0x32,0x1F,0x18,0x11,0x16,0x03,0x04,0x0D,0x0A,0x57,0x50,0x59,0x5E,0x4B,0x4C,0x45,0x42,0x6F,0x68,0x61,0x66,0x73,0x74,0x7D,0x7A,0x89,0x8E,0x87,0x80,0x95,0x92,0x9B,0x9C,0xB1,0xB6,0xBF,0xB8,0xAD,0xAA,0xA3,0xA4,0xF9,0xFE,0xF7,0xF0,0xE5,0xE2,0xEB,0xEC,0xC1,0xC6,0xCF,0xC8,0xDD,0xDA,0xD3,0xD4,0x69,0x6E,0x67,0x60,0x75,0x72,0x7B,0x7C,0x51,0x56,0x5F,0x58,0x4D,0x4A,0x43,0x44,0x19,0x1E,0x17,0x10,0x05,0x02,0x0B,0x0C,0x21,0x26,0x2F,0x28,0x3D,0x3A,0x33,0x34,0x4E,0x49,0x40,0x47,0x52,0x55,0x5C,0x5B,0x76,0x71,0x78,0x7F,0x6A,0x6D,0x64,0x63,0x3E,0x39,0x30,0x37,0x22,0x25,0x2C,0x2B,0x06,0x01,0x08,0x0F,0x1A,0x1D,0x14,0x13,0xAE,0xA9,0xA0,0xA7,0xB2,0xB5,0xBC,0xBB,0x96,0x91,0x98,0x9F,0x8A,0x8D,0x84,0x83,0xDE,0xD9,0xD0,0xD7,0xC2,0xC5,0xCC,0xCB,0xE6,0xE1,0xE8,0xEF,0xFA,0xFD,0xF4,0xF3 };

uint8_t CRC8(char *RP_ByteData,unsigned int Buffer_Size) {
 
 uint8_t x,R_CRC_Data;

 R_CRC_Data=0;

  for(unsigned int i = 0; i < Buffer_Size; i++) {
    x = R_CRC_Data ^ (*RP_ByteData);
    R_CRC_Data = xTable_CRC8[x];
    RP_ByteData++;
  }

 return R_CRC_Data;
}

这是我到目前为止尝试进行的转换：

  func calCR8(buf : [UInt8]) -> UInt8 {
    let initialValue : UInt8 = UInt8.min;
    let Table_CRC8 : [UInt8] = [
        0x00,0xF3 ];


        var crc = initialValue;
        let x: UInt8
    
    for i in 0 ..< buf.count{
            x = crc ^ buf
            crc = Table_CRC8[x]
        }

        return crc;
    }
}

我正在处理两个类型错误：无法将类型'[UInt8]'的值转换为预期的参数类型'UInt8'，并且无法将类型'UInt8'的值转换为预期参数类型“ Int” 。我在这里感到很失落和不舒服。

基本上，将以如下方式调用此函数：

var buf : [UInt8] = [0x00,0x00,0x00];
    buf[0] = 0xAA;
    buf[1] = 0x14;
    buf[2] = ~0x14
    buf[buf.count - 1] = self.calcCR8(buf)

基于此字节数组在本示例中使用参数，我期望返回0xC6。

解决方法

您有一些小错误。首先，您尝试对buf执行xor计算-这是整个数组；您需要访问单个元素buf[i]。

第二个问题是您无法用UInt8索引序列，因此您需要使Int等效才能访问Table_CRC8数组。

最后，您将x声明为let循环之外的for（常数），因此无法更改。您可以在x循环内移动for的声明来解决这个问题。

进行这些小的更改将使您可以编译代码：

for i in 0 ..< buf.count {
    let x = crc ^ buf[i]
    crc = Table_CRC8[Int(x)]
}

通过更改CRC表的名称以使其符合Swift习惯用法，并使用迭代循环而不是for in <range>循环，可以使其更加“快速”：

func calcCRC8(_ buf : [UInt8]) -> UInt8 {
    let tableCRC8 : [UInt8] = [
        0x00,0x07,0x0E,0x09,0x1C,0x1B,0x12,0x15,0x38,0x3F,0x36,0x31,0x24,0x23,0x2A,0x2D,0x70,0x77,0x7E,0x79,0x6C,0x6B,0x62,0x65,0x48,0x4F,0x46,0x41,0x54,0x53,0x5A,0x5D,0xE0,0xE7,0xEE,0xE9,0xFC,0xFB,0xF2,0xF5,0xD8,0xDF,0xD6,0xD1,0xC4,0xC3,0xCA,0xCD,0x90,0x97,0x9E,0x99,0x8C,0x8B,0x82,0x85,0xA8,0xAF,0xA6,0xA1,0xB4,0xB3,0xBA,0xBD,0xC7,0xC0,0xC9,0xCE,0xDB,0xDC,0xD5,0xD2,0xFF,0xF8,0xF1,0xF6,0xE3,0xE4,0xED,0xEA,0xB7,0xB0,0xB9,0xBE,0xAB,0xAC,0xA5,0xA2,0x8F,0x88,0x81,0x86,0x93,0x94,0x9D,0x9A,0x27,0x20,0x29,0x2E,0x3B,0x3C,0x35,0x32,0x1F,0x18,0x11,0x16,0x03,0x04,0x0D,0x0A,0x57,0x50,0x59,0x5E,0x4B,0x4C,0x45,0x42,0x6F,0x68,0x61,0x66,0x73,0x74,0x7D,0x7A,0x89,0x8E,0x87,0x80,0x95,0x92,0x9B,0x9C,0xB1,0xB6,0xBF,0xB8,0xAD,0xAA,0xA3,0xA4,0xF9,0xFE,0xF7,0xF0,0xE5,0xE2,0xEB,0xEC,0xC1,0xC6,0xCF,0xC8,0xDD,0xDA,0xD3,0xD4,0x69,0x6E,0x67,0x60,0x75,0x72,0x7B,0x7C,0x51,0x56,0x5F,0x58,0x4D,0x4A,0x43,0x44,0x19,0x1E,0x17,0x10,0x05,0x02,0x0B,0x0C,0x21,0x26,0x2F,0x28,0x3D,0x3A,0x33,0x34,0x4E,0x49,0x40,0x47,0x52,0x55,0x5C,0x5B,0x76,0x71,0x78,0x7F,0x6A,0x6D,0x64,0x63,0x3E,0x39,0x30,0x37,0x22,0x25,0x2C,0x2B,0x06,0x01,0x08,0x0F,0x1A,0x1D,0x14,0x13,0xAE,0xA9,0xA0,0xA7,0xB2,0xB5,0xBC,0xBB,0x96,0x91,0x98,0x9F,0x8A,0x8D,0x84,0x83,0xDE,0xD9,0xD0,0xD7,0xC2,0xC5,0xCC,0xCB,0xE6,0xE1,0xE8,0xEF,0xFA,0xFD,0xF4,0xF3 ];
    
    
    var crc = UInt8.min
    
    for byte in buf {
        let x = crc ^ byte
        crc = tableCRC8[Int(x)]
    }
    
    return crc
}