结果始终不是数字

如何解决结果始终不是数字

我对以下代码有疑问。当我为代码提供合适的整数和字符串值时，结果始终不是数字。我尝试将整数与* 1相乘，还尝试将整数var解析为int，但没有任何效果。

module.exports = async function CalculateUV(context,req) {
    context.log('JavaScript HTTP trigger function processed a request.');

   
    const stringA = (req.query.stringA || (req.body && req.body.stringA));
    const stringB = (req.query.stringB || (req.body && req.body.stringB));
    const stringC = (req.query.stringC || (req.body && req.body.stringC));

    var integerA = (req.query.integerA || (req.body && req.body.integerA));
    var integerB = (req.query.integerB || (req.body && req.body.integerB));
    var integerC = (req.query.integerC || (req.body && req.body.integerC));
    var integerD = (req.query.integerD || (req.body && req.body.integerD));
  
    

    var result;

    if (stringA == 'hello' && stringB == 'world') {

       switch (stringC) {
                case 'one':
                    result = 0;
                    break;
                case 'two':
                    result = (integerA + integerB) * (+integerD / 100);
                    break;
                case 'three':
                    result = (integerA + integerB) * (intergerD / 100);
                    break;
                case 'four':
                    result = (integerC) * (integerD / 100);
                    break;
                default:
                    result = 0;
            }
    }
    else {
        result = 'Error';
    }
    
     context.res = {
       // status: 200,/* Defaults to 200 */
        body: 'The result value is:' + result
     };
}

解决方法

执行此操作：

结果=（+ integerA + + integerB）*（integerD / 100）; 休息;

或者，

结果= 在加法过程中使用数字字符串时需要小心。即使您在查询中输入了数字值，Req.query也是一个字符串。 这就是为什么要使用NaN的原因，因为您是在将字符串与数字相乘。

其他运算符（*，/，-），请勿执行此操作。因此，无需为他们这样做。

,

req.query.x始终是一个字符串（因为它是从url导出的）。您需要将其解析为Int：

function CalculateUV (req) {
    const stringA = (req.query.stringA || (req.body && req.body.stringA));
    const stringB = (req.query.stringB || (req.body && req.body.stringB));
    const stringC = (req.query.stringC || (req.body && req.body.stringC));

    var integerA = (parseInt(req.query.integerA,10) || (req.body && req.body.integerA));
    var integerB = (parseInt(req.query.integerB,10) || (req.body && req.body.integerB));
    var integerC = (parseInt(req.query.integerC,10) || (req.body && req.body.integerC));
    var integerD = (parseInt(req.query.integerD,10) || (req.body && req.body.integerD));
  
    

    var result;

    if (stringA == 'hello' && stringB == 'world') {

      switch (stringC) {
        case 'one':
            result = 0;
            break;
        case 'two':
            result = (integerA + integerB) * (+integerD / 100);
            break;
        case 'three':
            result = (integerA + integerB) * (integerD / 100);
            break;
        case 'four':
            result = (integerC) * (integerD / 100);
            break;
        default:
            result = 0;
      }
    } else {
      result = 'Error';
    }
    const res = {
      body: 'The result value is:' + result
    };
    console.log(res);
}


const req = {
  query: {
    stringA: 'hello',stringB: 'world',stringC: 'three',integerA: '1',integerB: '2',integerC: '3',integerD: '4',},body: {
      stringA: 'four',stringB: 'five',stringC: 'six',integerA: 5,integerB: 6,integerC: 7,integerD: 8,}
CalculateUV(req);

请注意，如果parseInt（req.query.integerX，10）返回0，它将被视为false，并且var integerX将计算表达式的第二部分（在||之后）

PS：您在case 'three'中有一个错字，intergerD应该是integerD。

,

var integerA = (req.query.integerA || (req.body && req.body.integerA));
var integerB = (req.query.integerB || (req.body && req.body.integerB));
var integerC = (req.query.integerC || (req.body && req.body.integerC));
var integerD = (req.query.integerD || (req.body && req.body.integerD));

用波纹管替换上面的行

     var integerA = parseInt(req.query.integerA || (req.body && req.body.integerA));
var integerB = parseInt(req.query.integerB || (req.body && req.body.integerB));
var integerC = parseInt(req.query.integerC || (req.body && req.body.integerC));
var integerD = parseInt(req.query.integerD || (req.body && req.body.integerD));

也请像下面的波纹管一样删除integerD之前的+

result = (integerA + integerB) * (integerD / 100);

现在应该可以正常工作