如何解决如何使用python输入更新mysql
我正在尝试做一个简单的程序来用作contact_book,但是当我尝试更新行时却无法解决错误。 这是代码:
MysqL.connector.errors.ProgrammingError: 1064 (42000): You have an error in your sql Syntax; check
the manual that corresponds to your MysqL server version for the right Syntax to use near '''nome'' =
''Ivone'' WHERE index_num = ''2''' at line 1
将所有输入放到一个变量中,然后再提交给INSERT联系人的相同语法,但是在更新时出现错误:
<template>
<div class="swiper-container">
<!-- Additional required wrapper -->
<div class="swiper-wrapper">
<!-- Slides -->
<div class="swiper-slide">Slide 1</div>
<div class="swiper-slide">Slide 2</div>
<div class="swiper-slide">Slide 3</div>
...
</div>
<!-- If we need pagination -->
<div class="swiper-pagination"></div>
<!-- If we need navigation buttons -->
<div class="swiper-button-prev"></div>
<div class="swiper-button-next"></div>
<!-- If we need scrollbar -->
<div class="swiper-scrollbar"></div>
</div>
</template>
<script>
import Swiper,{ Navigation,Pagination } from 'swiper'
import 'swiper/swiper-bundle.css'
Swiper.use([ Navigation,Pagination ])
export default {
mounted() {
new Swiper('.swiper-container',{
loop: true,pagination: {
el: '.swiper-pagination',},navigation: {
nextEl: '.swiper-button-next',prevEl: '.swiper-button-prev',scrollbar: {
el: '.swiper-scrollbar',})
}
}
</script>
<style scoped>
.swiper-container {
width: 600px;
height: 300px;
}
</style>
解决方法
在执行之前,您需要在查询中提供字段名称:
editar = (para,index,)
然后:
sql = "UPDATE contato SET %s = %%s WHERE index_num = %%s" % (oque)
或
sql = "UPDATE contato SET {} = %s WHERE index_num = %s".format(oque)```
或(python 3.6 +)
sql = f"UPDATE contato SET {oque} = %s WHERE index_num = %s"
然后:
my_cursor.execute(sql,editar)
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