如何解决为什么Neo4j的父节点和子节点之间存在链接
1。我创建了Tweet和TweetLeaf节点,然后使用以下代码创建了空间布局
MERGE (n:Tweet {id:'13084664',title:'A'})
MERGE (cl1:TweetLeaf {id:'13085170',title:'AB',reply_to:'13084664'})
MERGE (cl2:TweetLeaf {id:'13085179',title:'TESTING Team',reply_to:'13085170'})
MERGE (cl2:TweetLeaf {id:'13085352',reply_to:'13085170'})
MERGE (cl4:TweetLeaf {id:'13085443',retweet_to:'13085352'})
MERGE (cl5:TweetLeaf {id:'13085356',retweet_to:'13085352'})
//parent and leaf.....
MATCH (parent:Tweet)
MATCH (c:TweetLeaf)
WHERE NOT (c)-[:reply]->()
AND parent.id = c.reply_to
WITH parent,c
MERGE (c)-[:reply_to]->(parent)
//RETURN c,parent
//leaf to leaf reply_to.....
MATCH (c1:TweetLeaf)-[]-()
WHERE exists (c1.reply_to)
MATCH (d1:TweetLeaf)
WHERE NOT (d1)-[]->() and exists (d1.reply_to)
AND c1.id = d1.reply_to
WITH c1,d1
MERGE (d1)-[:reply_to]->(c1)
//RETURN c1,d1
//leaf to leaf retweet_to....
MATCH (c2:TweetLeaf)
WHERE exists (c2.retweet_to)
AND NOT (c2)-[]->()
MATCH (d2:TweetLeaf)-[]->()
WHERE d2.id = c2.retweet_to
WITH c2,d2
MERGE (c2)-[:retweet_to]->(d2)
//RETURN c2,d2
但是,在我的输出中,节点A和节点AB之间没有链接。屏幕截图显示了我的输出图
解决方法
您用于生成可视化的查询显然只返回了table1
个节点,因此neo4j浏览器仅显示了这些节点。
相反,请尝试使用此查询(该查询返回长度为0或1的所有路径,其中包含TweetLeaf
节点):
TweetLeaf
如果存在独立的MATCH p=(:TweetLeaf)-[*0..1]-()
RETURN p
节点,则长度为0的路径将没有关系。如果您不关心这种情况,则可以改用TweetLeaf
。
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