合并传感器数据数组的最佳方法

如何解决合并传感器数据数组的最佳方法

我正在使用AHRS库来创建传感器融合的位置数据数组。

从Go Pro遥测数据中，我得到了加速度计，陀螺仪和磁力计数据阵列，并为每个具有以下形状的样本添加了时间戳：

{
  ACCEL: {
     samples: [{time,data},...]
  },....
}

我想将它们合并成一个对象

{
  time: {accel,gyro,magn}
  ...
}

每个时间戳具有全部3个值

我已经与减速器一起使用

const magn = result[1].streams['MAGN'].samples.reduce((prev,next) => {
    return {...prev,[next.cts]: {magn: next.value}}
},{})

const gyro = result[1].streams['GYRO'].samples.reduce((prev,next) => {
    const closest = prev[Object.keys(prev).reverse()?.find(key => key < next.cts) || Object.keys(prev)[0]]
    return {...prev,[next.cts]: {...closest,gyro: next.value}}
},magn)

const merged = result[1].streams['ACCL'].samples.reduce((prev,accel: next.value}}
},gyro)

但这似乎不是很优雅的代码。

有没有更有效的方法来处理它？

解决方法

打字稿playground

type Input = Record<string,{ samples: { time: number,data: any }[] }>

type Output = Record<'number',{ [K in keyof Input]: any }>

const inp: Input = { ACCEL: { samples: [{ time: 12,data: '12data' },{ time: 14,data: '14data' }]},GYRO: { samples: [{ time: 18,data: 'gyro18' },{ time: 12,data: 'gyro12' }] }};

const keyOfInput = Object.keys(inp)

const collectionOfTimes =  [
  ... new Set(
    keyOfInput
      .map(key => inp[key].samples.map(s => s.time))
      .reduce((acc,curr) => [...acc,...curr],[]))
]

const out: Output = collectionOfTimes.reduce((acc,time) => ({ ...acc,[time]: 
  keyOfInput.reduce((acc2,key) => ({...acc2,[key]: inp[key].samples.find(i => i.time === time)?.data || null}),{})
}),{} as Output);

console.log(out);

/*
[LOG]: { "12": { "ACCEL": "12data","GYRO": "gyro12" },"14": { "ACCEL": "14data","GYRO": null },"18": { "ACCEL": null,"GYRO": "gyro18" } } 
*/

在typescriptlang.org上编译为js

"use strict";
const inp = { ACCEL: { samples: [{ time: 12,data: '14data' }] },data: 'gyro12' }] } };
const keyOfInput = Object.keys(inp);
const collectionOfTimes = [
    ...new Set(keyOfInput
        .map(key => inp[key].samples.map(s => s.time))
        .reduce((acc,[]))
];
const out = collectionOfTimes.reduce((acc,time) => (Object.assign(Object.assign({},acc),{ [time]: keyOfInput.reduce((acc2,key) => { var _a; return (Object.assign(Object.assign({},acc2),{ [key]: ((_a = inp[key].samples.find(i => i.time === time)) === null || _a === void 0 ? void 0 : _a.data) || null })); },{}) })),{});
console.log(out);
/*
[LOG]: { "12": { "ACCEL": "12data","GYRO": "gyro18" } }
*/