该程序仍会抛出InputMismatchException并退出，即使已被捕获

如何解决该程序仍会抛出InputMismatchException并退出，即使已被捕获

我只是在学习Java，并且正在努力处理异常。我正在尝试编写一个快速程序，该程序接受一些输入并将它们转换为不同的单位。

我正在使用Scanner接收输入，并且试图防止InputMisatchException，但是尽管在它周围放置了try-catch块来处理异常，但它仍然存在。代码是波纹管的。希望能对您有所帮助！预先感谢。

import java.util.InputMismatchException;

import java.util.Scanner;

class Main {
  public static void main(String[] args) {
    
    //init variables
    String name = "";
    int age = -1;
    int height_in_cm = -1;

    //Init Scanner
    Scanner input = new Scanner(system.in);

    //Get the input from the user and save to the initiated variables above.
    System.out.print("Please enter your name: ");
    name = input.nextLine();
    try{
    System.out.printf("hey,%s. How old are you?: ",name);
    age = input.nextInt();
    } catch (InputMismatchException e){
        System.out.printf("Agh! Sorry %s. We were expecting a number made up of digits between 0-9. Try again for us? \n How old are you?: ",name);
        age = input.nextInt();
    }
    System.out.print("And finally,what is your height in CM?: ");
    height_in_cm = input.nextInt();

    //close the scanner to protect from resource leaks.
    input.close();


  }
}```

解决方法

您还需要尝试一下

height_in_cm = input.nextInt();

否则，您将获得另一个例外！

,

发生异常的原因是，当第一次引发异常时，扫描程序（输入）不会更新其指针，因此catch块中的input.nextInt()会读取与{{1 }}。

要解决此问题，请在读取int值之前在catch块中添加input.nextInt()。

input.nextLine()

,

原因是您在catch块中捕获了错误。尝试为其实现一个循环。还请记住使用input.next();清除缓冲区，否则您将遇到无限循环

do
{
    try
    {
        System.out.printf("Hey,%s. How old are you?: ",name);
        age = input.nextInt();
        stop = true;
    } 
    catch (InputMismatchException e)
    {
        System.out.printf("Agh! Sorry %s. We were expecting a number made up of digits between 0-9. Try again for us? \n How old are you?: ",name);
        input.next(); // Clearing the buffer. This is important otherwise Infinite Loop will occur
    }
} while( !stop );