在循环中从arr [i]的值制作python列表的一部分

如何解决在循环中从arr [i]的值制作python列表的一部分

list1 = [1,4,16,64]
right = []
left = []
for i in range(len(list1)):
    pass

i = 1 || arr[1] = 4 || left = [1] || right = [16,64]
i = 2 || arr[2] = 16 || left = [1,4] || right = [64]

根据arr [i]的值将列表分为两部分。例如：如果i = 1，则值为4。那么列表中所有小于4的值都应放在左侧列表中，而所有大于4的值都应放在左侧列表中4应该继续

解决方法

您可以分割列表。左边可以从开头到i，右边可以从i + 1到结尾

list1 = [1,4,16,64].sort()
right = []
left = []

for i in range(len(list1)):
    right = list1[i+1:]
    left = list1[:i]
    print(f"i = {i} || arr[{i}] = {list1[i]} || left = {left} || right = {right}")

输出：

i = 0 || arr[0] = 1 || left = [] || right = [4,64]
i = 1 || arr[1] = 4 || left = [1] || right = [16,64]
i = 2 || arr[2] = 16 || left = [1,4] || right = [64]
i = 3 || arr[3] = 64 || left = [1,16] || right = []

,

这对您有帮助：

list1 = [1,64]
right = []
left = []

for i in range(len(list1)):
    if list1[i] <= 4:
        left.append(list1[i])
    else:
        right.append(list1[i])
    print(f"i = {i} || arr[{i}] = {list1[i]} || left = {left} || right = {right}")

输出：

i = 0 || arr[0] = 1 || left = [1] || right = []
i = 1 || arr[1] = 4 || left = [1,4] || right = []
i = 2 || arr[2] = 16 || left = [1,4] || right = [16]
i = 3 || arr[3] = 64 || left = [1,4] || right = [16,64]