是否有必要在zappa package命令中提供aws环境名称？

如何解决是否有必要在zappa package命令中提供aws环境名称？

我有一个小flask应用程序，想使用zappa将其转换为aws lambda函数。

我的方法： 我不想在执行zappa init时手动提供所有详细信息，所以我将所有这些信息作为zappa_settings.json文件提供了

zappa_settings.json

{
    "test": {
        "app_function": "flask.main.app","aws_region": "us-east-1","profile_name": "test","project_name": "flask","runtime": "python3.6","s3_bucket": "zappa_test_bucket"
    },"stage": {
        "app_function": "flask.main.app","profile_name": "stage","s3_bucket": "zappa_stage_bucket"
    },"prod": {
        "app_function": "flask.main.app","profile_name": "prod","s3_bucket": "zappa_prod_bucket"
    }


}

如果我们看到上面的文件，我有3个不同的环境。除了s3_bucket和profile_name之外，所有其他变量都具有相同的数据。

现在，我具有生成脚本，该脚本将生成一个压缩文件并将该文件上传到s3存储桶中。

       1. create a package using `zappa package <test/stage/prod> -o mypackage.zip`  and 
             2. build script will put this zipped file into s3 bucket.
             3. later on with the help of CI/CD,lambda receives zipped file and do the process.

我的问题

    1. Is it necessary to provide aws_environment name in the `zappa package <test/stage/prod> -o mypackage.zip`  command ?
    2. If yes,How can i write a single build script which will create a package(zappa package) for all 3 environments?

可以提出建议。