如何序列化可以作为其自身类型参数的泛型类？

如何解决如何序列化可以作为其自身类型参数的泛型类？

编辑2：问题已解决。约阿希姆·绍尔（Joachim Sauer）和病毒拉拉基亚（Viral Lalakia）的道具。

解决方案：：如果我将Comparable<T>和Serializable交换为T类型，SonarLint不会发出警告。它发出的警告应被认为是误报。

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初始问题：

因此，我有一个通用类Pair<T>，我想成为Serializable和Comparable。 此外，我想要 T成为Comparable（而我需要将Serializable变成Pair<T>也可以序列化。）

类PairCoord继承自其中，其中T是Integer。

我正在使用SonarLint进行代码分析，并且我正试图强迫自己听从每条建议（尤其是非常重要的建议），并且它一直在警告我有关通用类Pair的属性未被可序列化的东西，尽管已经将它们标记为这样。

这是我所做的：

public class Pair<T extends Comparable<? super T> & Serializable> implements Comparable<Pair<T>>,Serializable {

    private static final long serialVersionUID = 5797102044530257848L;
    
    
    private T first;
    private T last;

    public Pair(T first,T last) {
        this.first = first;
        this.last = last;
    }
    public Pair() {
    }

    // And so on
}

public class PairCoord extends Pair<Integer> implements Serializable {

    private static final long serialVersionUID = 8389593640798914292L;
    

    public PairCoord(int first,int last) {
        super(first,(last + 8) % 8);
        // Since each of the 3 squares are loops,the node before n°0 is therefore n°-1
        // Except that n°-1 doesn't exist,but (-1 mod 8) = 7 
        // The only issue is that % isn't a modulo,but the remain of the euclidean division
        // So by adding 8 to "last",I make sure that the number in the operation is positive,// and since for all x >= 0,% behaves like mod,I have my node number correct (between 0 and 7) 
    }

}

而且我在first和last字段上有SonarLint严重警告，因为它们无法序列化，即使我将它们标记为可序列化（“ Serializable”类中的字段也应该是瞬态或可序列化”）

该如何解决（如果可能）？

（编辑1：错字）

解决方法

private static final long serialVersionUID = 5797102044530257848L;

private T first;
private T last;

public Pair(T first,T last) {
    this.first = first;
    this.last = last;
}
public Pair() {
}

// And so on

}

公共类PairCoord扩展Pair实现Serializable {

private static final long serialVersionUID = 8389593640798914292L;


public PairCoord(int first,int last) {
    super(first,(last + 8) % 8);
    // Since each of the 3 squares are loops,the node before n°0 is therefore n°-1
    // Except that n°-1 doesn't exist,but (-1 mod 8) = 7 
    // The only issue is that % isn't a modulo,but the remain of the euclidean division
    // So by adding 8 to "last",I make sure that the number in the operation is positive,// and since for all x >= 0,% behaves like mod,I have my node number correct (between 0 and 7) 
}

}