API不再连接

如何解决API不再连接

项目：我正在构建一个宁静的API，该API从一个API提取数据，并使用另一个API将部分数据（描述）转换为其他词典。

问题：一切正常，直到几天前我停止与翻译API的连接。我没有更改与请求有关的代码。当我使用VCS返回到较早版本的代码时，我也可以复制该问题。我已经在两个不同的环境中尝试过此操作，但是遇到了相同的问题。我也尝试过使用Web浏览器和 POSTMAN ，但它们似乎得到了适当的响应。 运行测试文件但未从翻译API获得所需的响应时，我收到的HTTP代码为200。

代码说明：因此，我从我的第一个API（数据）中获取了一些嵌套信息flavor_text_entries，并将其用作描述，将其设置为变量并将其发送给我的翻译API仅翻译并返回描述的翻译。

def extract_descriptive_text(json_blob,language='en',version='sword'):
    text = ""
    for f in json_blob['flavor_text_entries']:
        if f['language']['name'] == language and f['version']['name'] == version:
            text = f['flavor_text'] 
    return text


def extract_useful_info(translated):
    text = []
    wanted_info = translated['contents']['translated']
    text.append(wanted_info)
    return text


@app.route('/pokemon/<string:name>/',methods=['GET'])
def get_translation(name):
    descrip_url = f"https://pokeapi.co/api/v2/pokemon-species/{name}"
    r = requests.get(descrip_url)
    json_blob = r.json()
    text_trans = extract_descriptive_text(json_blob)
    trans_url = f"https://api.funtranslations.com/translate/shakespeare.json?text={text_trans}"
    shakespeare = requests.get(trans_url)
    translated = shakespeare.json()
    useful_info = extract_useful_info(translated)
    return jsonify({'name': name,'description': useful_info})

if __name__ == '__main__':
    app.run(debug=True)

错误，当我尝试从翻译API返回所有内容时得到提示：

ERROR:
{
  "name": "charizard","description": {
    "error": {
      "code": 404,"message": "Not Found"
    }
  }
}

跟踪，当我尝试只返回翻译时收到：

Traceback (most recent call last):
  File "/Users/swapneel/Library/Python/3.8/lib/python/site-packages/flask/app.py",line 2464,in __call__
    return self.wsgi_app(environ,start_response)
  File "/Users/swapneel/Library/Python/3.8/lib/python/site-packages/flask/app.py",line 2450,in wsgi_app
    response = self.handle_exception(e)
  File "/Users/swapneel/Library/Python/3.8/lib/python/site-packages/flask_restful/__init__.py",line 272,in error_router
    return original_handler(e)
  File "/Users/swapneel/Library/Python/3.8/lib/python/site-packages/flask/app.py",line 1867,in handle_exception
    reraise(exc_type,exc_value,tb)
  File "/Users/swapneel/Library/Python/3.8/lib/python/site-packages/flask/_compat.py",line 39,in reraise
    raise value
  File "/Users/swapneel/Library/Python/3.8/lib/python/site-packages/flask/app.py",line 2447,in wsgi_app
    response = self.full_dispatch_request()
  File "/Users/swapneel/Library/Python/3.8/lib/python/site-packages/flask/app.py",line 1952,in full_dispatch_request
    rv = self.handle_user_exception(e)
  File "/Users/swapneel/Library/Python/3.8/lib/python/site-packages/flask_restful/__init__.py",line 1821,in handle_user_exception
    reraise(exc_type,line 1950,in full_dispatch_request
    rv = self.dispatch_request()
  File "/Users/swapneel/Library/Python/3.8/lib/python/site-packages/flask/app.py",line 1936,in dispatch_request
    return self.view_functions[rule.endpoint](**req.view_args)
  File "/Users/swapneel/Desktop/projects/foobar/main.py",line 58,in get_translation
    useful_info = extract_useful_info(translated)
  File "/Users/swapneel/Desktop/projects/foobar/main.py",line 21,in extract_useful_info
    wanted_info = translated['contents']['translated']
KeyError: 'contents'

使用的库和软件包：

from flask import Flask,jsonify
from flask_restful import Api
import requests

任何帮助将不胜感激！

解决方法

翻译API找不到搜索词xxxx.dkr.ecr.region.amazonaws.com/aws-appmesh-envoy:v1.15.0.0-prod，并且返回的JSON与您期望的能够处理的JSON不同。

在charizard中，您正在检索extract_useful_info()，但是正如您在API响应中所看到的那样，当API错误时，您将得到该密钥不存在的信息。相反，响应包含translated['contents']和'name'。

您需要对API错误发生时进行检查。您可以通过例如将'description'包裹在wanted_info中：

try/except

作为旁注：我不明白为什么def extract_useful_info(translated): text = [] try: wanted_info = translated['contents']['translated'] except KeyError: wanted_info = '' text.append(wanted_info) return text 需要成为列表。如果只是字符串，则代码变得更加简单

text

如果是这样，我们可以完全摆脱def extract_useful_info(translated): try: return translated['contents']['translated'] except KeyError: return '' # return None is better but I don't know if your app can handle that. 并这样做

extract_useful_info()