如何解决如何将我插入的ID从Firebase传递到下一个表单
我是新来对本机做出反应的,所以我只能将输入文本中的数据存储到firebase并制作登录表单。 我想制作一个用于调查的应用程序,有一个用于调查数据的表单输入,然后将id调查传递给下一个表单(用户表单)。 我可以在CI或wordpress上执行此操作,但不能在本机上执行此操作
像这样的流
调查表单--- 发送ID插入的Firebase --->用户表单 -> 保存最终数据
import React,{ Component } from 'react';
import {
Button,StyleSheet,TextInput,ScrollView,ActivityIndicator,View,Text,SafeAreaView,TouchableOpacity
} from 'react-native';
import {Ionicons} from "@expo/vector-icons"
import firebase from 'firebase';
export default class PostScreen extends Component {
constructor() {
super();
this.dbRef = firebase.firestore().collection('surveys');
this.state = {
usia: '',kab: '',kec: '',desa: '',rw: '',rt: '',jekel: '',tps: '',isLoading: false
};
}
inputValueUpdate = (val,prop) => {
const state = this.state;
state[prop] = val;
this.setState(state);
}
storesurveys() {
if(this.state.usia === ''){
alert('Masukan usia anda!')
}else {
this.setState({
isLoading: true,});
this.dbRef.doc(this.state.usia).set({
usia: this.state.usia,kab: this.state.kab,kec: this.state.kec,desa: this.state.desa,rw: this.state.rw,rt: this.state.rt,jekel: this.state.jekel,tps: this.state.tps,}).then((res) => {
this.setState({
usia: '',isLoading: false,});
this.props.navigation.navigate('Dummy')
})
.catch((err) => {
console.error("Error found: ",err);
this.setState({
isLoading: false,});
});
}
}
render() {
if(this.state.isLoading){
return(
<View style={styles.preloader}>
<ActivityIndicator size="large" color="#9E9E9E"/>
</View>
)
}
return (
<SafeAreaView style={styles.container}>
<View style={styles.header}>
<TouchableOpacity onPress={()=> this.props.navigation.goBack()}>
<Ionicons name="md-arrow-back" size={24} color="#D8D9DB"></Ionicons>
</TouchableOpacity>
<TouchableOpacity>
<Text style={{fontWeight:"500"}}>Formulir surveys</Text>
</TouchableOpacity>
</View>
<ScrollView style={styles.inputForm}>
<View style={styles.inputGroup}>
<TextInput
placeholder={'usia'}
value={this.state.usia}
onChangeText={(val) => this.inputValueUpdate(val,'usia')}
/>
</View>
<View style={styles.inputGroup}>
<TextInput
placeholder={'kab'}
value={this.state.kab}
onChangeText={(val) => this.inputValueUpdate(val,'kab')}
/>
</View>
<View style={styles.inputGroup}>
<TextInput
placeholder={'kec'}
value={this.state.kec}
onChangeText={(val) => this.inputValueUpdate(val,'kec')}
/>
</View>
<View style={styles.inputGroup}>
<TextInput
placeholder={'desa'}
value={this.state.desa}
onChangeText={(val) => this.inputValueUpdate(val,'desa')}
/>
</View>
<View style={styles.inputGroup}>
<TextInput
placeholder={'rw'}
value={this.state.rw}
onChangeText={(val) => this.inputValueUpdate(val,'rw')}
/>
</View>
<View style={styles.inputGroup}>
<TextInput
placeholder={'rt'}
value={this.state.rt}
onChangeText={(val) => this.inputValueUpdate(val,'rt')}
/>
</View>
<View style={styles.inputGroup}>
<TextInput
placeholder={'jekel'}
value={this.state.jekel}
onChangeText={(val) => this.inputValueUpdate(val,'jekel')}
/>
</View>
<View style={styles.inputGroup}>
<TextInput
placeholder={'tps'}
value={this.state.tps}
onChangeText={(val) => this.inputValueUpdate(val,'tps')}
/>
</View>
<View style={styles.button}>
<Button
title='Add Survey'
onPress={() => this.storesurveys()}
color="#19AC52"
/>
</View>
</ScrollView>
</SafeAreaView>
);
}
}
用户表格 注意:我需要将调查表传递给我的用户表,并从调查中插入ID
import React,TouchableOpacity
} from 'react-native';
import {Ionicons} from "@expo/vector-icons"
import firebase from 'firebase';
export default class PostScreen extends Component {
constructor() {
super();
this.dbRef = firebase.firestore().collection('penduduk');
this.state = {
nik: '',nama: '',tgl_lahir: '',usia: '',survey: '',prop) => {
const state = this.state;
state[prop] = val;
this.setState(state);
}
storePenduduk() {
if(this.state.nik === ''){
alert('Masukan NIK anda!')
}else if(this.state.nama === ''){
alert('Masukan Nama anda!')
}else {
this.setState({
isLoading: true,});
this.dbRef.doc(this.state.nik).set({
nik: this.state.nik,nama: this.state.nama,tgl_lahir: this.state.tgl_lahir,usia: this.state.usia,survey : this.state.survey,}).then((res) => {
this.setState({
nik: nik,});
});
}
}
render() {
if(this.state.isLoading){
return(
<View style={styles.preloader}>
<ActivityIndicator size="large" color="#9E9E9E"/>
</View>
)
}
return (
<SafeAreaView style={styles.container}>
<View style={styles.header}>
<TouchableOpacity onPress={()=> this.props.navigation.goBack()}>
<Ionicons name="md-arrow-back" size={24} color="#D8D9DB"></Ionicons>
</TouchableOpacity>
<TouchableOpacity>
<Text style={{fontWeight:"500"}}>Formulir Penduduk</Text>
</TouchableOpacity>
</View>
<ScrollView style={styles.inputForm}>
<View style={styles.inputGroup}>
<TextInput
placeholder={'nik'}
value={this.state.nik}
onChangeText={(val) => this.inputValueUpdate(val,'nik')}
/>
</View>
<View style={styles.inputGroup}>
<TextInput
placeholder={'nama'}
value={this.state.nama}
onChangeText={(val) => this.inputValueUpdate(val,'nama')}
/>
</View>
<View style={styles.inputGroup}>
<TextInput
placeholder={'tgl_lahir'}
value={this.state.tgl_lahir}
onChangeText={(val) => this.inputValueUpdate(val,'tgl_lahir')}
/>
</View>
<View style={styles.inputGroup}>
<TextInput
placeholder={'usia'}
value={this.state.usia}
onChangeText={(val) => this.inputValueUpdate(val,'usia')}
/>
</View>
<View style={styles.inputGroup}>
<TextInput
placeholder={'jekel'}
value={this.state.jekel}
onChangeText={(val) => this.inputValueUpdate(val,'jekel')}
/>
</View>
<View style={styles.inputGroup}>
<TextInput
placeholder={'survey'}
value={this.state.survey}
onChangeText={(val) => this.inputValueUpdate(val,'survey')}
/>
</View>
<View style={styles.button}>
<Button
title='Add User'
onPress={() => this.storePenduduk()}
color="#19AC52"
/>
</View>
</ScrollView>
</SafeAreaView>
);
}
}
解决方法
您可以在add()之后获得插入的ID;
firebase.firestore().collection("SurveyForm").add({
// inserted values
}). then((docRef) => { const insertedId = docRef.id } })
,
第一个屏幕
this.dbRef.doc(this.state.usia).set({
usia: this.state.usia,kab: this.state.kab,kec: this.state.kec,desa: this.state.desa,rw: this.state.rw,rt: this.state.rt,jekel: this.state.jekel,tps: this.state.tps,}).then((res) => {
const insertedId = res.id
this.setState({
usia: '',kab: '',kec: '',desa: '',rw: '',rt: '',jekel: '',tps: '',isLoading: false,});
this.props.navigation.navigate('Dummy',{id: insertedId})
})
.catch((err) => {
console.error("Error found: ",err);
this.setState({
isLoading: false,});
});
第二屏幕:
render() {
if(this.state.isLoading){
const text = this.props.navigation.getParam('id','new id');
return(
<View style={styles.preloader}>
<ActivityIndicator size="large" color="#9E9E9E"/>
</View>
)
}
必须遵守this答案的所有规则,以便您可以在下一个屏幕上ID
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