Python：Tika：parser.open_filefilepath无法正确打开文件” PermissionError：[Errno 13]权限被拒绝：”

如何解决Python：Tika：parser.open_filefilepath无法正确打开文件” PermissionError：[Errno 13]权限被拒绝：”

此刻我正在使用Tika，我努力使它工作。我有以下代码：

import tika
import logging
from tika import parser
tika.initVM()
import os
from Tool.settings import Settings

settings = Settings() # setting.UPLOAD_DIRECTORY = 'C:\\Users\\username\\Projects\\Tool/uploaded_files'

The settings looks something like this:
# class Settings:
#     def __init__(self):
#         self.ROOTDIR = "{}".format(os.path.dirname(os.path.dirname(os.path.abspath(__file__))))
#         self.UPLOAD_DIRECTORY = r"{}/uploaded_files".format(self.Tool_DIR)


def convert_pdf_to_text(filepath):
    tika.initVM()
    logging.info('Started Tika server')
    raw_data = parser.from_file(filepath)
    return raw_data['content'],raw_data['Metadata']

def get_text(path):
    text,Metadata = convert_pdf_to_text(path)
    return text,Metadata

class document_split():
    def __init__(self,path):
        self.path = settings.UPLOAD_DIRECTORY
        self.file = os.path.basename(path)
        self.settings = Settings()
        self.raw_data,self.Metadata = get_text(self.path)


class converted_files():
    def __init__(self,type):
        self.company = type
        self.settings = Settings()
        self.UPLOAD_DIRECTORY = settings.UPLOAD_DIRECTORY
        self.dictionary = self.create_dictionary

    @property
    def create_dictionary(self):
        loaded_files = {}

        for file in os.listdir(self.UPLOAD_DIRECTORY):
            fp = os.path.join(settings.UPLOAD_DIRECTORY,file)
            loaded_file = Document(fp)
            print(loaded_file)
            value = loaded_file
            key = loaded_file.date
            loaded_files[key] = value
            print(value)

        print('Loaded {} files'.format(len(loaded_files)))
        return loaded_files

我的问题在于这部分：

for file in os.listdir(self.UPLOAD_DIRECTORY):
                fp = os.path.join(settings.UPLOAD_DIRECTORY,file)
                loaded_file = Document(fp)
                print(loaded_file)
                value = loaded_file
                key = loaded_file.date
                loaded_files[key] = value
                print(value)

它给我以下错误：

如果_is_file_object（urlOrPath）否则以urlOrPath打开（path，'rb'）as f： PermissionError：[Errno 13]权限被拒绝：'C：\ Users \ user \ Projects \ Tool / uploaded_files'

当我对如下路径进行硬编码时，它不会给出此错误消息：

r'C:\\Users\\user\\Projects\\Tool/uploaded_files'

所以现在我正在努力寻找一种方法来r'进入打开文件的路径...有人可以帮助我吗？