如何解决如何使用AWK将CSV文件转换为TOML哈希表
我想使用AWK将CSV文件转换为TOML。我的输入看起来像这样:
id,name,lifetime
adam,Adam,1550-1602
eve,Eve,1542-1619
而我正在努力做到这一点
[adam]
name = "Adam"
lifetime = "1550-1602"
[eve]
name = "Eve"
lifetime = "1542-1619"
我编写了以下AWK小脚本,但效果不佳:
BEGIN {
FS=","
}
NR == 1 {
nc = NF
for (c = 1; c <= NF; c++) {
h[c] = $c
}
}
NR > 1 {
for(c = 1; c <= nc; c++) {
printf h[c] "= " $c "\n"
}
print ""
}
END {
}
到目前为止的结果是
id = adam
name = Adam
lifetime= 1550-1602
id = eve
name = Eve
lifetime= 1542-1619
根据记录,我的AWK版本是GNU Awk 4.1.4
解决方法
请您尝试按照GNU awk
中的示例进行跟踪,编写和测试。
awk -F'[[:space:]]*,[[:space:]]*' -v s1="\"" '
FNR==1{
for(i=2;i<=NF;i++){
gsub(/^ +| +$/,"",$i)
arr[i]=$i
}
next
}
{
print "["$1"]"
for(i=2;i<=NF;i++){
print " "arr[i]" = "s1 $i s1
}
}' Input_file
说明: 添加上述解决方案的详细说明。
awk -F'[[:space:]]*,[[:space:]]*' -v s1="\"" ' ##Starting awk program from here,setting field separator as space comma space and creating variable s1 which has " in it.
FNR==1{ ##Checking condition if this is first line then do following.
for(i=2;i<=NF;i++){ ##Run a for loop from 2nd field to last field in current line.
gsub(/^ +| +$/,$i) ##Globally substituting spaces from starting or ending to NULL in current field.
arr[i]=$i ##Creating arr with index of i and value of $i here.
}
next ##next will skip all further statements from here.
}
{
print "["$1"]" ##Printing [ first field ] here.
for(i=2;i<=NF;i++){ ##Running loop from 2 to till last field of line here.
print " "arr[i]" = "s1 $i s1 ##Printing arr value with index i and s1 current field s1 here.
}
}' Input_file ##Mentioning Input_file name here.
注意: OP的示例Input_file的第一行中有空格以删除它们gsub(/^ +| +$/,$i)
正在使用,如果在第一行的末尾没有找到空格,请删除此行输入文件的行。
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